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3 years ago

5

A symmetric data distribution is shown. Which addition of data will have the greatest effect on the mean?

1 answer:

Alex3 years ago

4 0

If with symmetrical data, asymmetrical data is added, it will have a great effect on the mean.

<u>Explanation:</u>

Symmetrical data is the data or the situation in which the values of the variables occur at the same or the regular intervals. The mean, median and mode occur at the same point of this symmetrical distribution.

Since this distribution is in a particular symmetry and occur at regular intervals, they do not skew, unlike in the case of the asymmetrical distribution. If you fold the histogram in half of the symmetrical distribution, it looks about the same on both sides.

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One of the base angles of an isosceles triangle is 40°. Which is the triangle classification according to its

kozerog [31]

Answer:

C. Obtuse

Step-by-step explanation:

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vovikov84 [41]

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2 years ago

Divide -2x^3-5x^2+4x+2 by x+2

erik [133]

<u>Answer</u><u>: </u>

The correct option is C. $-2x^2-x+6, R(-10)$

<u> Explanation: </u>

<u>Given:</u>

Dividend = -2x^3-5x^2+4x+2

Divider =(x+2)

<u>Solution</u>:

Now by using the division method , we will find out the quotient and remainder of the given equation

And the equation will become

$-2x^3-5x^2+4x+2=(x+2)(-2x^2-x+6)-10$

So , We will get the quotient = $-2x^2-x+6$

And Remainder = -10

Hence the Correct option which perfectly satisfy the given equation is C.

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2 years ago

What kind of function is 3y-2=x+7

Phoenix [80]

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3 years ago

The rate of change of revenue (in dollars per calculator) from the sale of x calculators is R′(x)=(x+1)ln(x+1)R ′ (x)=(x+1)ln(x+

jekas [21]

Answer:

Total revenue = $\frac{169}{2}\ln(13)-\frac{169}{4}$ dollars

Step-by-step explanation:

$R'(x)=(x+1)\ln(x+1)$

Integrate with respect to $x$ .

$R(x)=$ ∫ $(x+1)\ln(x+1)$ dx

Take $x+1=u$

Differentiate with respect to $x$

$dx=du$

So,

$R(x)=$ ∫ $u\ln(u)\,du$

Use integration by parts: ∫f g dx = f∫ g dx-∫(∫g dx)f' dx

Therefore,

$R(x)=$ $\frac{u^2}{2}\ln(u)$ $-$ ∫ $\frac{u^2}{2}\frac{1}{u}\,du$

= $\frac{u^2}{2}\ln(u)$ $-$ ∫ $\frac{u}{2}\,du$

Put $u=x+1$

$R(x)= \frac{(x+1)^2}{2}\ln(x+1)-\frac{(x+1)^2}{4}$

To find total revenue from the sale of the first 12 calculators, put $x=12$

$R(x)= \frac{(12+1)^2}{2}\ln(12+1)-\frac{(12+1)^2}{4}\\\\= \frac{(13)^2}{2}\ln(13)-\frac{(13)^2}{4}\\\\=\frac{169}{2}\ln(13)-\frac{169}{4}$

Total revenue = $\frac{169}{2}\ln(13)-\frac{169}{4}$ dollars

4 0

2 years ago