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Sidana [21]
3 years ago
9

I need help please and thank you

Mathematics
1 answer:
marta [7]3 years ago
5 0
So what u need to do is

46+x=180 and u will get the answer
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A quantitative observation? a. contains a number and a unit b. does not contain a number c. always makes a comparison
Naily [24]

Answer: A. contains a number and a unit

Step-by-step explanation:

Quantitative observations measure the quantity, or the amount, of a certain thing. Therefore they must always use a number value to measure the amounts, and a unit to signify what the amount is for.

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2 years ago
Whatbis the slope of a line that is perpendicular to the line y= 2x-6? A. -2
ICE Princess25 [194]

Answer:

D. -1/2

Step-by-step explanation:

When a line is perpendicular to another line the slope will be the exact opposite. For example line A = y = 3x + 5 the line perpendicular to it will be -1/3x.

So -1/2 is the slope of your perpendicular line.

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3 years ago
Pythagorean Theorem
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A tennis player moves in a straight-line path as shown in the figure below. find her average velocity in the following time inte
Andreyy89
To find the average velocity in a velocity-time graph at a particular interval, simply determine the gradient at that particular interval. 

<span>a. average velocity= 4/1 </span>
<span>= 4m/s </span>

<span>b. average velocity from 1 to 2.5s= 6/(2.5-1) </span>
<span>= 4m/s </span>

<span>average velocity from 2.5 to 4.0s= 0m/s </span>

<span>average velocity from 0 to 4.0s= (4+0)/4 </span>
<span>= 1m/s </span>

<span>c. average velocity from 1.0 to 4.0s= (4/3)m/s </span>

<span>average velocity from 4.0 to 5.0s= 2/1 </span>
<span>= 2.0m/s </span>

<span>average velocity from 1.0 to 5.0s= ((4/3)+2)/4 </span>
<span>= (5/6)m/s </span>

<span>d. average velocity from 0 to 4.0s= 1.0m/s </span>

<span>average velocity from 4.0 to 5.0s= 2.0m/s </span>

<span>average velocity from 0 to 5.0s= (1.0+2.0)/5 </span>
<span>= (3/5)m/s </span>
4 0
3 years ago
Listed below is data on profit and market capitalization for a sample of 15 different firms in U.S. Profit is the y variable and
MissTica

Answer:

Step-by-step explanation:

Hello!

You have two study variables:

Dependent variable

Y: Profit of the firm in the U.S.

Independent variable

X: Market capitalization of the firm

a.

See the scatterplot in the attachment.

Looking at the graphic it seems that there is a positive regression between the profit and the market capitalization, meaning that every time the market capitalization of the firm increases, the profit of this firm also increases. But not all the "firms" adjust linearly, so I wouldn't expect the regression to be powerful.

b.

The regression model is E(Yi)= α + βXi

Where the parameters of the model are α and β, these two parameters are to be estimated to estimate the regression equation. The estimator for α is a and the estimator for β is b:

a= Y[bar] - bX[bar]

b= [∑XY-(∑X*∑Y)/n]/[∑X²-(∑X)²/n]

I'll use a statistic software to calculate the estimated regression equation:

^Yi= a + bXi

^Yi= 325.89 + 0.07Xi

c.

You need to predict the value of Y (Profit) given a value of X= 70721.3 (million). To make this prediction you have to use the estimated equation:

^Yi= 325.89 + 0.07Xi

^Yi= 325.89 + 0.07(70721.3)= 5276.381

The predicted profit for a market capitalization value of 70,721.3 is 5276.381 million.

I hope this helps!

6 0
3 years ago
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