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3 years ago

The graph below represents the relationship between the force exerted on an elevator and the distance the elevator is lifted.

1 answer:

8 0

I have three problems with this question.

#1). If you copied the question exactly the way it's written,
then the question is written very badly. The wording is
misleading, and the more you try to think about it and
puzzle it out, the more it'll damage your understanding
of Physics.

There is no relationship between the force exerted on an
elevator and the distance the elevator is lifted.

-- If the force is anything more than the weight of the elevator ...
even one ounce more ... then it'll lift the elevator as high as
you want.

-- If the force is anything less than the weight of the elevator ...
even one ounce less, then that elevator is headed for the bottom.

#2). You didn't post any graph below, so if we need the graph
to answer the question, then we can't answer the question.

#3). I guess that's OK, because you didn't ask any question.

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Eric, Sheena, and Yael are playing a game. Eric has half as many points as Sheena. Sheena has two fewer points than Yael. Togeth

nexus9112 [7]

Lets say that:

Eric is E

Sheena is S

Yael is Y

We know that S+2=Y, E= 1/S and that E+S+Y=52. So, we can insert S+2=Y and E= 1/S into our other equation, which would bring us to (1/2S)+(S+2)+S=52. This is equal to 1/2S+S+2+S=52. We then use algebra to get the answer:

Given:

S+2=Y

E=1/S

E+Y+S=52

Equation:

1/2S+S+2+S=52

1/2S+S+S=52

2.5S=50

S=50/2.5

S=20

And since Yael has 2 more points then Yael then we do 20+2 and get 22.

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3 years ago

A 0.600 kg block is attached to a spring with spring constant 15 N/m. While the block is sitting at rest, a student hits it with

gulaghasi [49]

Answer:

8.8 cm

31.422 cm/s

Explanation:

m = Mass of block = 0.6 kg

k = Spring constant = 15 N/m

x = Compression of spring

v = Velocity of block

A = Amplitude

As the energy of the system is conserved we have

$\dfrac{1}{2}mv^2=\dfrac{1}{2}kA^2\\\Rightarrow A=\sqrt{\dfrac{mv^2}{k}}\\\Rightarrow A=\sqrt{\dfrac{0.6\times 0.44^2}{15}}\\\Rightarrow A=0.088\ m\\\Rightarrow A=8.8\ cm$

Amplitude of the oscillations is 8.8 cm

At x = 0.7 A

Again, as the energy of the system is conserved we have

$\dfrac{1}{2}kA^2=\dfrac{1}{2}mv^2+\dfrac{1}{2}kx^2\\\Rightarrow v=\sqrt{\dfrac{k(A^2-x^2)}{m}}\\\Rightarrow v=\sqrt{\dfrac{15(0.088^2-(0.7\times 0.088)^2)}{0.6}}\\\Rightarrow v=0.31422\ m/s$

The block's speed is 31.422 cm/s

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3 years ago

Which sentence in the passage can be used to conclude that Eris is a dwarf planet and not a planet?

Lelu [443]

Eris is slightly more massive than Pluto. However, both of them are smaller than Earth's Moon.
This should conclude that Eris is a dwarf planet.

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3 years ago

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Reptile [31]

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2 years ago

An airplane is cruising at a speed of 250 m/s. If the airplanes engines provide a forward force of 19,540 N, calculate the force

ExtremeBDS [4]

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3 years ago