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rosijanka [135]
3 years ago
6

Light does not move infinitely fast but has a finite speed. We normally use ""c"" to indicate the speed of light in science. Wri

te down the value for the speed of light in metric units: c = _________.
Physics
1 answer:
Ede4ka [16]3 years ago
5 0

Answer:

6.71 × 10^8 mi/hr

Explanation:

Light is usually defined as an electromagnetic wave that is comprised of a definite wavelength. It is of both types, visible and invisible. The light emitted from a source usually travels at a speed of about 3 × 10^8 meter/sec. This speed of light is commonly represented by the letter 'C'.

To write it in the metric system, it has to be converted into miles/hour.

We know that,

1 minute = 60 seconds

60 minutes = 1 hour

1 kilometer = 1000 meter

1 miles = 1.6 kilometer

Now,

= \frac{3 \times\ 10^8 meter \times\ 60 sec \times\ 60 min}{1 sec \times\ 1 min \times\ 1 hr}

= 1.08 × 10^12 m/ hr (meter/hour)

= \frac{1.08 \times\ 10^{12} meter \times\ 1 km \times\ 1 miles}{1 hr \times\ 1000 meter \times\ 1.6 km}

= 6.71 × 10^8 mi/hr (miles/hour)

Thus, the value for speed of light (C) in metric unit is 6.71 × 10^8 mi/hr.

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Answer:

The scientific method is a method of research with defined steps that include experiments and careful observation. One of the most important aspects of this method is the testing of hypotheses by means of repeatable experiments. A hypothesis is a suggested explanation for an event, which can be tested.

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Which type of nuclear reaction involves combining light elements into a heavier element, with a resultant release of great amoun
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_{94}^{239}\textrm{Pu}+_2^4\textrm{He}\rightarrow _{96}^{242}\textrm{Cm}+_0^\textrm{n}

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Consider a string with a length of (47.5 A) cm tied at both end (like on a stringed instrument). If the frequency of the first h
zubka84 [21]

To solve this problem it is necessary to apply the concepts related to wavelength as a function of frequency and speed, as well as to determine the wavelength as a function of length.

From the harmonic vibration generated we know that the total length of the string will be equivalent to a half of the wavelength, that is

L = \frac{\lambda}{2} \rightarrow \lambda = 2L

Where,

\lambda = Wavelength

Therefore the wavelength for us would be,

\lambda = 2*47.5cm = 95cm = 0.95m

From the relationship of speed, frequency and wavelength we know that

\lambda = \frac{v}{f} \rightarrow v = \lambda f

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v = 232.75 m/s

Therefore the speed of the wave is 232.75m/s

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3 years ago
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