If the temperature outside increases from 30 degrees to 60 degrees, how has the kinetic energy of the air particles changed?
2 answers:
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Answer:
I = 20 i ^ N s
Explanation:
For this problem let's use the Impulse equation
I = Δp = m - v₀
The impulse and the velocity are vector quantities, let's calculate on each axis, let's decompose the velocity
cos 60 = vₓ / v
vₓ = v cos 60
sin60 = / v
= v sin60
vₓ = 10 cos 60
= 10 sin60
vₓ = 5.0 m / s
= 8.66 m / s
Let's calculate the impulse on each axis
X axis
Iₓ = m - m vₓ₀
How the ball bounces
= - vₓ₀ = vₓ
Iₓ = 2 m vₓ
Iₓ = 2 2 5
Iₓ = 20 N s
Y axis
= m
- m vyo
On the axis and the ball does not change direction so
= vyo
= 0
The total momentum is
I = Iₓ i ^ + j ^
I = 20 i ^ N s
a) The angular velocity of the electron is
b) The number of revolutions per second is rev/s
c) The centripetal acceleration of the electron is
Explanation:
a)
This is a problem of uniform circular motion: in fact, the electron orbits around the proton in a uniform circular motion.
The angular velocity of an object in uniform circular motion is given by
where
v is the linear speed
r is the radius of the trajectory
For the electron orbiting around the proton, we have
Therefore, the angular velocity is
b)
The period of revolution of the electron is given by
where
is the angular velocity
Substituting,
The period is the time the electron takes to make one complete orbit around the proton; therefore, the number of revolutions of the electrons in one second is:
rev/s
c)
The centripetal acceleration of an object in circular motion is
where
v is the linear speed
r is the radius of the circle
For the electron, we have
Therefore, the centripetal acceleration is
Learn more about circular motion:
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