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inysia [295]
3 years ago
6

A store has a bargain bin filled with red (R), blue (B), pink (P), and yellow (Y) shirts in sizes small (S) and large (L). Which

outcomes are possible when randomly pulling one shirt from the bin?
A) {S, L}
B) {R, B, P, Y}
C) {RS, BS, PS, YS}
Eliminate
D) {RS, RL, BS, BL, PS, PL, YS, YL}
Mathematics
2 answers:
olasank [31]3 years ago
7 0

Option D:

Possible outcomes when randomly pulling one shirt from the bin are

RS, RL, BS, BL, PS, PL, YS, YL

Solution:

<u>Color of shirts are: </u>

Red (R), Blue(B), Pink(P), Yellow(Y).

<u>Size of shirts are: </u>

Small(S), Large(L)

This means that each color of shirts have both in small and large size.

<u>Shirts in bargain bin are:</u>

Red in Small (RS), Red in Large (RL)

Blue in Small (BS), Blue in Large (BL)

Pink in Small (PS), Pink in Large (PL)

Yellow in Small (YS), Yellow in Large (YL)

<u>Possible outcomes when randomly pulling one shirt are:</u>

RS, RL, BS, BL, PS, PL, YS, YL

Hence Option D is the correct answer.

andrew11 [14]3 years ago
6 0

Answer:

d

Step-by-step explanation:

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Step-by-step explanation:

x + 3y = 24.....multiply by -1

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3 years ago
A restaurant sells about 330 sandwiches each day at a price of $6 each $.25 decrease in price. 15 more sandwiches are sold per d
zmey [24]

Answer:

restaurant should charge $(6-0.25) = $5.75per sandwich to maximize daily revenue.

the revenue is $1983.75

Step-by-step explanation:

to calculate current revenue= $6 x 330 = $1980

suppose x as the number of times the price to be dropped by $0.25

then find new price.. i.e

new price= $(6-0.25x)

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(6-0.25x)(330 +15x)

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now, to make a complete square lets add and subtract 1 inside the parentheses

=1980-3.75(-1+1-2x+x^{2})

=1980 +3.75 -3.75(x^{2} -2x +1)

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as (x-1)^{2} is positive always, minimize the other term in order to maximize the total revenue.

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putting x in eq(1) the revenure becomes,

$(1983.75-0)=> $1983.75

therefore, restaurant should charge $(6-0.25) = $5.75per sandwich to maximize daily revenue.

the revenue is $1983.75

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