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3 years ago

Point U is on line segment TV. Given UV = 2, TU = 5x, and TV = 3x + 6,

Mathematics

2 answers:

Anna007 [38]3 years ago

8 0

Answer:

TV = 12

Step-by-step explanation:

TV = TU + UV

3x + 6 = 5x + 2

Shift the unknowns to the left, constants to the right.

3x - 5x = 2 - 6

-2x = -4

Divide both sides by -2.

x = 2

Substitute x = 2 into the equation for TV (3x + 6),

3x + 6

= 3(2) + 6

= 6 + 6

= 12

amm18123 years ago

5 0

Answer:

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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3 years ago

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Anastaziya [24]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

In the graph below, Point A represents Owen's house, Point B represents David's house and Point C represents the school. Who liv

ycow [4]

Answer:

• David

• 4 miles

Explanation:

In the graph:

The given locations are:

• Owen's House, A(11,3)

• David's House, B(15,13)

• School, C(3,18)

We determine both Owen's and David's distance from the school using the distance formula.

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Owen's distance from school (AC)

$\begin{gathered} AC=\sqrt[]{(3-11)^2+(18-3)^2} \\ =\sqrt[]{(-8)^2+(15)^2} \\ =\sqrt[]{64+225} \\ =\sqrt[]{289} \\ AC=17\text{ miles} \end{gathered}$

David's distance from school (BC)

$\begin{gathered} BC=\sqrt[]{(3-15)^2+(18-13)^2} \\ =\sqrt[]{(-12)^2+(5)^2} \\ =\sqrt[]{144+25} \\ =\sqrt[]{169} \\ BC=13\text{ miles} \end{gathered}$

We see from the calculations that David lives closer to the school, and by 4 miles.

The graph below is attached for further understanding: