Answer:
\left(3+i\right)y\left(3-i\right)=10y
Step-by-step explanation:
\left(3+i\right)y\left(3-i\right)
\left(3+i\right)\left(3-i\right)y
=y\cdot \:10
=10y
Answer:
No Solution
Step-by-step explanation:
There are no values of b
that make the equation true.
No solution
I believe this question logically tells us to find the value of w. The two equations are already equated. Since there is 1 unknown and 1 equation, the system is solvable. The solution is as follows:
5/(6w+21) = -1/3(2w - 9)
5/(6w+21) = -1/(6w - 27)
Cross multiplying the terms:
5(6w - 27) = -1(6w +21)
30w - 135 = -6w - 21
30w + 6w = -21 + 135 = 114
36w = 114
w = 114/36
w = 19/6 or 3.167
