Answer: 0.1824
Step-by-step explanation:
Given : The mileage per day is distributed normally with
Mean : 
Standard deviation : 
Let X be the random variable that represents the distance traveled by truck in one day .
Now, calculate the z-score :-

For x= 132 miles per day.

For x= 159 miles per day.

Now by using standard normal distribution table, the probability that a truck drives between 132 and 159 miles in a day will be :-

Hence, the probability that a truck drives between 132 and 159 miles in a day =0.1824
Answer: The answer should be 9.2195
Step-by-step explanation:They tell us the point is 2.9 and they are asking the distance from the origin which is zero. So we can use pythagorean theorem. A²+B²=C² Look at it as a triangle. They have given us A and B, so you can find C² using those information. If you plot the point in the line you know that A=2 and B=9. Using the formula will be 2²+9²=C² ⇒ 4+81=C² ⇒ 85=C². To get rid of the power of 2 in c we have to square both side to cancel it out. C would equal 9.2195
A.A is your best answer
A vertex is "the apex" of the angle.
See attached photo.
hope this helps
T=10H+100
T being your total, and H is the hours worked.