All categories

3 years ago

What is the radius of a circle with circumstance of 22m

1 answer:

3 0

Circumference of a circle = 2πr = 22
2 * 22/7 * r = 22
r = 22 * 7 /44
r = 7/2

In short, Your Answer would be 7/2 m or 3.5 m

Hope this helps!

You might be interested in

There are 480 soccer balls on a field. Every hour, half of the balls are put back into the locker room. Write an equation that c

Mrac [35]

Answer:

$y= 480-0.5x$

Step-by-step explanation:

Given data

Number of balls= 480

we are told that 50%(half) of the balls are put back every 1

let the number of hours be x

and let the remaining ball be y after x hours

Hence the expression is given as

$y= 480-0.5x$

3 0

3 years ago

1/5 divided by N equals 1/3

8090 [49]

Answer:

N=3/5

Step-by-step explanation:

(1/5)/N=1/3

N=(1/5)/(1/3)

N=(1/5)(3/1)

N=3/5

6 0

3 years ago

1. There are always twice as many girls as boys in school. Mathematical expression

Airida [17]

Answer:

Boys x 2 = Girls

Step-by-step explanation:

If there are twice as many girls in school as boys than take the number of boys and multiply that by 2. For example if there are 400 boys in school and there are twice as many girs your equation would, 400 x 2 = 800 girls.

8 0

3 years ago

Read 2 more answers

Determine the above sequence converges or diverges. If the sequence converges determine its limit

marshall27 [118]

Answer:

This series is convergent. The partial sums of this series converge to $\displaystyle \frac{2}{3}$ .

Step-by-step explanation:

The $n$ th partial sum of a series is the sum of its first $n\!\!$ terms. In symbols, if $a_n$ denote the $n\!$ th term of the original series, the $\! n$ th partial sum of this series would be:

$\begin{aligned} S_n &= \sum\limits_{k = 1}^{n} a_k \\ &= a_1 + a_2 + \cdots + a_{k}\end{aligned}$ .

A series is convergent if the limit of its partial sums, $\displaystyle \lim\limits_{n \to \infty} S_{n}$ , exists (should be a finite number.)

In this question, the $n$ th term of this original series is:

$\displaystyle a_{n} = \frac{{(-1)}^{n+1}}{{2}^{n}}$ .

The first thing to notice is the ${(-1)}^{n+1}$ in the expression for the $n$ th term of this series. Because of this expression, signs of consecutive terms of this series would alternate between positive and negative. This series is considered an alternating series.

One useful property of alternating series is that it would be relatively easy to find out if the series is convergent (in other words, whether $\displaystyle \lim\limits_{n \to \infty} S_{n}$ exists.)

If $\lbrace a_n \rbrace$ is an alternating series (signs of consecutive terms alternate,) it would be convergent (that is: the partial sum limit $\displaystyle \lim\limits_{n \to \infty} S_{n}$ exists) as long as $\lim\limits_{n \to \infty} |a_{n}| = 0$ .

For the alternating series in this question, indeed:

$\begin{aligned}\lim\limits_{n \to \infty} |a_n| &= \lim\limits_{n \to \infty} \left|\frac{{(-1)}^{n+1}}{{2}^{n}}\right| = \lim\limits_{n \to \infty} {\left(\frac{1}{2}\right)}^{n} =0\end{aligned}$ .

Therefore, this series is indeed convergent. However, this conclusion doesn't give the exact value of $\displaystyle \lim\limits_{n \to \infty} S_{n}$ . The exact value of that limit needs to be found in other ways.

Notice that $\lbrace a_n \rbrace$ is a geometric series with the first term is $a_0 = (-1)$ while the common ratio is $r = (- 1/ 2)$ . Apply the formula for the sum of geometric series to find an expression for $S_n$ :

$\begin{aligned}S_n &= \frac{a_0 \cdot \left(1 - r^{n}\right)}{1 - r} \\ &= \frac{\displaystyle (-1) \cdot \left(1 - {(-1 / 2)}^{n}\right)}{1 - (-1/2)} \\ &= \frac{-1 + {(-1 / 2)}^{n}}{3/2} = -\frac{2}{3} + \frac{2}{3} \cdot {\left(-\frac{1}{2}\right)}^{n}\end{aligned}$ .

Evaluate the limit $\displaystyle \lim\limits_{n \to \infty} S_{n}$ :

$\begin{aligned} \lim\limits_{n \to \infty} S_{n} &= \lim\limits_{n \to \infty} \left(-\frac{2}{3} + \frac{2}{3} \cdot {\left(-\frac{1}{2}\right)}^{n}\right) \\ &= -\frac{2}{3} + \frac{2}{3} \cdot \underbrace{\lim\limits_{n \to \infty} \left[{\left(-\frac{1}{2}\right)}^{n} \right] }_{0}= -\frac{2}{3}\end{aligned}}_$ .

Therefore, the partial sum of this series converges to $\displaystyle \left(- \frac{2}{3}\right)$ .

8 0

3 years ago

Please help ASAP! Due tonight!

Trava [24]

Answer:

D. x = √17

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Trigonometry

Pythagorean Theorem: a² + b² = c²

Step-by-step explanation:

Step 1: Define

leg a = 4

leg b = 1

hypotenuse c = x

Step 2: Solve for x

Substitute: 4² + 1² = x²
Exponents: 16 + 1 = x²
Add: 17 = x²
Isolate x: √17 = x
Rewrite: x = √17

3 0

3 years ago