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riadik2000 [5.3K]
3 years ago
9

A bag contains 5 black marbles, 9 white marbles, and 2 red marbles. One marble is to be chosen at random. What is the probabilit

y that the chosen marble will be red?
A. 1/16

B.1/8

C. 1/3

D.1/2
Mathematics
2 answers:
swat323 years ago
8 0
I will go with B. because there's 2 red marbles and there's 16 marbles in total and you will have to simplify  that and get 1/8.
Ugo [173]3 years ago
5 0
5 + 9 + 2 = 16 
We choose one of sixteen, =>
A. 1/16
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1

P(V|A) is not 0.95. It is opposite:

P(A|V)=0.95

From the text we can also conclude, that

P(A|∼V)=0.1

P(B|V)=0.9

P(B|∼V)=0.05

P(V)=0.01

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What you need to calculate and compare is P(V|A) and P(V|B)

P(V∩A)=P(A)⋅P(V|A)⇒P(V|A)=P(V∩A)P(A)

P(V∩A) means, that Joe has a virus and it is detected, so

P(V∩A)=P(V)⋅P(A|V)=0.01⋅0.95=0.0095

P(A) is sum of two options: "Joe has virus and it is detected" and "Joe has no virus, but it was mistakenly detected", therefore:

P(A)=P(V)⋅P(A|V)+P(∼V)⋅P(A|∼V)=0.01⋅0.95+0.99⋅0.1=0.1085

7 0
3 years ago
A box contains marbles of five different colors: red, green, blue, yellow, and purple. there is an equal number of each color. a
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P(red) = 1/5     [that says "probability of getting red is one fifth"
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The reason the fractions are all the same is that there are equal numbers of each color.  For example, if there were 7 marbles of each color, there would be a total of 35 marbles.

P(red) = 7/35 = 1/5
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Hope that this helped!
4 0
3 years ago
I have like 20 minutes please help<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D-7x%2B10%3D0" id="TexFormula1" title="x^{2}-7x+10
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Step-by-step explanation:

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