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P(V|A) is not 0.95. It is opposite:
P(A|V)=0.95
From the text we can also conclude, that
P(A|∼V)=0.1
P(B|V)=0.9
P(B|∼V)=0.05
P(V)=0.01
P(∼V)=0.99
What you need to calculate and compare is P(V|A) and P(V|B)
P(V∩A)=P(A)⋅P(V|A)⇒P(V|A)=P(V∩A)P(A)
P(V∩A) means, that Joe has a virus and it is detected, so
P(V∩A)=P(V)⋅P(A|V)=0.01⋅0.95=0.0095
P(A) is sum of two options: "Joe has virus and it is detected" and "Joe has no virus, but it was mistakenly detected", therefore:
P(A)=P(V)⋅P(A|V)+P(∼V)⋅P(A|∼V)=0.01⋅0.95+0.99⋅0.1=0.1085
P(red) = 1/5 [that says "probability of getting red is one fifth"
P(green) = 1/5
P(blue) = 1/5
P(yellow) = 1/5
P(purple) = 1/5
The reason the fractions are all the same is that there are equal numbers of each color. For example, if there were 7 marbles of each color, there would be a total of 35 marbles.
P(red) = 7/35 = 1/5
Similar for the other colors.
It's letter c
multiply the coefficient then just add the degrees of each letter
The possible values for | x-y | > 0 is any number above 0. x must be greater than y. When | x-y | = 0, That means that x and y are equal to each other. | x-y | can not be less than 0, but it can equal 0.
Hope that this helped!
Answer: Hmm Ok i do this-
Step-by-step explanation:
Wait are we trying to find x?
Ok so for the first one x = 5 and for the second one x = 2