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riadik2000 [5.3K]
3 years ago
9

A bag contains 5 black marbles, 9 white marbles, and 2 red marbles. One marble is to be chosen at random. What is the probabilit

y that the chosen marble will be red?
A. 1/16

B.1/8

C. 1/3

D.1/2
Mathematics
2 answers:
swat323 years ago
8 0
I will go with B. because there's 2 red marbles and there's 16 marbles in total and you will have to simplify  that and get 1/8.
Ugo [173]3 years ago
5 0
5 + 9 + 2 = 16 
We choose one of sixteen, =>
A. 1/16
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zheka24 [161]

Answer:

f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )

Step-by-step explanation:

Let:

M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y

This is and exact equation, because:

\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}

So, define f(x,y) such that:

\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)

The solution will be given by:

f(x,y)=C_1

Where C1 is an arbitrary constant

Integrate \frac{\partial f(x,y)}{\partial x} with respect to x in order to find f(x,y):

f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}

Substitute into \frac{\partial f(x,y)}{\partial y} =N(x,y)

2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y

Integrate \frac{dg(y)}{dy} with respect to y:

g(y)=\int\ {8y} \, dy =4y^2

Substitute g(y) into f(x,y):

f(x,y)=2x^2+4y^2+2xy

The solution is f(x,y)=C1

f(x,y)=2x^2+4y^2+2xy=C_1

Solving y using quadratic formula:

y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )

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3 years ago
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4 0
2 years ago
Please find the value of x please
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Step by step explanation

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The first on is this answer here

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In a dance competition, a participant has to score a total of at least 30 points in the first four rounds combined to move on to
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Answer:

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