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Dvinal [7]
3 years ago
9

F Tell whether the statement is true or false.

Mathematics
1 answer:
Kitty [74]3 years ago
7 0

Answer:

A true

Step-by-step explanation:

It is the correct answer i have read this

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Jennifer hit a golf ball from the ground and it followed the projectile ℎ(t)= −15t^2+100t, where t is the time in seconds, and ℎ
oksano4ka [1.4K]

Answer:

Step-by-step explanation:

In order to find the max height the ball reached, we have to complete the square on that quadratic. That will also, conveniently so, give us the number of seconds it will take the ball to reach that max height, that answer to part b. Let's begin to complete the square. Normally, you would move the constant over to the other side of the equals sign, but there is no constant here. The next step is to get the leading coefficient to be a 1, and ours right now is a -15. So we have to factor it out. Here's where we start the process of completing the square.

-15(t^2-\frac{20}{3}t)=0 Next step is to take half the linear term, square it, and add it to both sides. Our linear term is 20/3. Half of 20/3 is 20/6, and 20/6 squared is 400/36.

-15(t^2-\frac{20}{3}t+\frac{400}{36})=0+??? Because this is an equation, what we add to the left side also has to be added to the right. BUT we didn't just add in 400/36, because we have that -15 out front as a multiplier that refuses to be ignored. What we actually added in was -15(400/36):

-15(t^2-\frac{20}{3}t+\frac{400}{36})=0-\frac{500}{3}

The reason we do this is to create a perfect square binomial on the left which will serve as the number of seconds, h, in the vertex (h, k), where h is the number of seconds it takes the ball to reach its max height, k. Simplifying both sides then gives us:

-15(t-\frac{20}{6})^2=-\frac{500}{3} Finally, we will move the right side over by the left and set the quadratic back equal to h(t):

h(t)=-15(t^2-\frac{20}{3})^2+\frac{500}{3} and from that you can determine that the vertex is (\frac{20}{3},\frac{500}{3}).

The answer to a. is vound in the second number of our vertex: k, the max height. The max of the golf ball was 500/3 feet or 166 2/3 feet.

Part b is found in the first number of the vertex: h, the number of seconds it took the golf ball to reach that max height. The time it took was 3 1/3 seconds.

Part c. is to state the domain (the time) and the range (the height) of the ball.

Domain is

D: {x | 0 ≤ x ≤ 3 1/3} and

Range is

R: {y | 0 ≤ y ≤ 166 2/3}

8 0
3 years ago
Hiiii could one of y’all help please. be 100% correct i’m having a hard time
ivanzaharov [21]

Answer:

other

Step-by-step explanation:


4 0
3 years ago
HELP ILL GIVE BRAINLIEST!!!!
Setler [38]

Its A i had the same one. Hope it helps.

8 0
3 years ago
Suppose you start at the origin, move along the x-axis a distance of 4 units in the positive direction, and then move downward a
Zanzabum

Answer:

(4,0,-5)

Step-by-step explanation:

Since we move 4 points along +ve x-axis so,  x coordinate is 4

We did not move any point along y-axis so  y coordinate is 0

we moved 5 points along -ve z-axis so z coordinate is -5

so our position is (x,y,z) = (4,0,-5)

3 0
3 years ago
A house and a lot are appraised at 212,400. If the value of the house is five times the value of the lot, how muchis the house w
JulsSmile [24]
It will be 1062000 because....
you multiply 202400 by 5
the key word in the reading is times
5 0
3 years ago
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