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Serhud [2]
3 years ago
5

Which of the following statements regarding e-mails is true?

Computers and Technology
2 answers:
Stells [14]3 years ago
7 0
E-mail passwords should be easy for you to remember, but not easy for someone else to figure out.
This statement <span>regarding e-mails is true.</span><span>
</span>
ANEK [815]3 years ago
4 0

Answer:

D. E-mail passwords should be easy for you to remember, but not easy for someone else to figure out.

Explanation:

Penn Foster --__--

jus got an 100% on gawd!!!

Thank god I finish Penn Foster with a 3.86 as my GPA!

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You are a trainer for your company and often teach courses in a classroom located on-campus or in a hotel conference room. In yo
Alisiya [41]

Answer:

Duplicate these displays.

Explanation:

<u>A. Show only on 1</u> <em>displays only the first screen and disconnects the second one</em>

<u>B. Extend these displays</u> <em>displays two different outputs on the same computer</em>

<u>C. Show only on 2.</u> <em>displays only the second screen and disconnects the first one</em>

<u>D. Duplicate these displays.</u> <em>displays the same output for both screen</em>

5 0
3 years ago
Read 2 more answers
Which data type is 2.5?
Phoenix [80]

2.5 is a float.

Float stands for floating point. Floating point types are numbers with decimal places. I hope this helps!

6 0
2 years ago
Consider an error-free 64 kbps satellite channel used to send 512 byte data frames in one direction, with very short acknowledge
Vladimir [108]

Answer:

The answer is "2".

Explanation:

In the given question some information is missing, that is "The propagation time for satellite to earth" which is "270 milliseconds" so, the description to this question can be defined as follows:

Given values:

Bandwidth = 64 kbps

Data frames = 512 bytes  

Propagation Time (t​​​​​​p ) =270 ms

Change Bandwidth  kbps to bps:

1 kb= 1024 bytes

calculated bandwidth= 64 kbps = 64×1024 bps = 65536 bps

1 bytes = 8 bits

512 bytes = 512 × 8 =  4096 bits

Frame length = 4096 bits

Formula

Transmission time (T​​​​​​t) = Frame length /Bandwidth

Window size = 1+2a

where a = Propagation time/Transmission time

Calculate Transmission time:

Transmission time (T​​​​​​t) = 4096 / 65536

Transmission time (T​​​​​​t)= 625 m.sec

Calculate Window size:

Window size = 1+2(270/625)

Window size = 1+2(0.432)

Window size = 1+0.864

Window size = 1.864

Window size = 2

3 0
3 years ago
The ______________________ denotes the application software and technology that concerns a wide range of topics from the data ma
zhuklara [117]

Answer:

System/application Domain.

Explanation:

System/application domain represents the technology and  software that is tasked to do diverse subjects from the data management to the systems that processes data or information.

Particular application domain has it's own specific virtual address in which the resources for the application domain are present that uses the address space.

8 0
3 years ago
A _______ contains several blades of differing thicknesses and is used to measure the clearance between parts.
motikmotik
A Feeler Gauge. It is a tool used to measure gap widths
3 0
3 years ago
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