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Mrac [35]
3 years ago
13

Suppose Client A initiates a Telnet session with Server S. At about the same time, Client B also initiates a Telnet session with

Server S. Provide possible source and destination port numbers for:
a. The segments sent from A to S.
b. The segments sent from B to S.
c. The segments sent from S to A.
d. The segments sent from S to B.
e. If A and B are different hosts, is it possible that the source port number in the segments from A to S is the same as that from B to S?
f. How about if they are the same host?
Computers and Technology
1 answer:
Shtirlitz [24]3 years ago
7 0

Answer:

Explanation:

From the given information;

We will like you to understand that the source port numbers and destination port number can be any number. For that reason, the ones being used here will just be examples.

NOTE:

That the destination port numbers sent from A to S and B to S are the same in their segments.

That the destination port numbers sent from S to A and S to B are the same in their segments.

From A to S, the segment sent possibly could have the source port number 467 and destination port number as 23(Telnet)

From B to S, the segment sent possibly could have the source port number 513 and destination port number as 23(Telnet).

From S to A, the segment sent possibly could have the source port number as 23(Telnet) and destination port number as 467.

From S to B, the segment sent possibly could have the source port number as 23(Telnet) and destination port number as 513.

Yes, it is possible. This is because the inclusion of  IP in the segments is to recognize the host.

No, the source ports will be different. Because source port number from A to S can't be the same from B to S at the time they are in the same host.

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2) Please create a C program for the following: (25 points) a. Suppose the US dollar to Korean Won is 0.85 dollars to 1000 won.
Zanzabum

Answer:

In C:

#include <stdio.h>

int main(){

       float won,usd,rupee,dinar,peso;

       printf("Won: ");

       scanf("%f", &won);

       usd = won * 0.85/1000;

       rupee = won * 0.85 * 0.14/1000;

       dinar = won * 0.85 * 0.048/1000;

       peso = won * 0.85 * 1.41/1000;

       printf("USD = %f\n", usd);

       printf("Rupee = %f\n", rupee);

       printf("Dinar = %f\n", dinar);

       printf("Peso = %f\n", peso);

   return 0;

}

Explanation:

This declares all variables as float

float won,usd,rupee,dinar,peso;

This prompts the user for Korean Won

       printf("Won: ");

This gets the input for won

       scanf("%f", &won);

This converts to usd

       usd = won * 0.85/1000;

This converts to rupee

       rupee = won * 0.85 * 0.14/1000;

This converts to dinar

       dinar = won * 0.85 * 0.048/1000;

This converts to peso

       peso = won * 0.85 * 1.41/1000;

The next four lines print the converted currencies

       printf("USD = %f\n", usd);

       printf("Rupee = %f\n", rupee);

       printf("Dinar = %f\n", dinar);

       printf("Peso = %f\n", peso);

3 0
3 years ago
C++
daser333 [38]

#include<iostream>

#include <fstream>

#include <vector>

#include <string>

#include "StatePair.h"

using namespace std;

int main() {

ifstream inFS;

int zip;

int population;

string abbrev;

string state;

unsigned int i;

vector<StatePair <int, string>> zipCodeState;

vector<StatePair<string, string>> abbrevState;

vector<StatePair<string, int>> statePopulation;

inFS.open("zip_code_state.txt");

if (!inFS.is_open()) {

    cout << "Could not open file zip_code_state.txt." << endl;

    return 1;

}

while (!inFS.eof()) {

    StatePair <int, string> temp;

    inFS >> zip;

    if (!inFS.fail()) {

        temp.SetKey(zip);

    }

    inFS >> abbrev;

    if (!inFS.fail()) {

        temp.SetValue(abbrev);

    }

    zipCodeState.push_back(temp);

}

inFS.close();

inFS.open("abbreviation_state.txt");

if (!inFS.is_open()) {

    cout << "Could not open file abbreviation_state.txt." << endl;

    return 1;

}

while (!inFS.eof()) {

    StatePair <string, string> temp;

    inFS >> abbrev;

    if (!inFS.fail()) {

        temp.SetKey(abbrev);

    }

    getline(inFS, state);

    getline(inFS, state);

    state = state.substr(0, state.size()-1);

    if (!inFS.fail()) {

        temp.SetValue(state);

    }

    abbrevState.push_back(temp);

}

inFS.close();

inFS.open("state_population.txt");

if (!inFS.is_open()) {

    cout << "Could not open file state_population.txt." << endl;

    return 1;

}

while (!inFS.eof()) {

    StatePair <string, int> temp;

    getline(inFS, state);

    state = state.substr(0, state.size()-1);

    if (!inFS.fail()) {

        temp.SetKey(state);

    }

    inFS >> population;

    if (!inFS.fail()) {

        temp.SetValue(population);

    }

    getline(inFS, state);

    statePopulation.push_back(temp);

}

inFS.close();

cin >> zip;

for (i = 0; i < zipCodeState.size(); ++i) {

 }

for (i = 0; i < abbrevState.size(); ++i) {

 }

for (i = 0; i < statePopulation.size(); ++i) {

}

}

Statepair.h

#ifndef STATEPAIR

#define STATEPAIR

#include <iostream>

using namespace std;

template<typename T1, typename T2>

class StatePair {

private:

T1 key;

T2 value;

public:

StatePair()

{}

void SetKey(T1 key)

{

this->key = key;

}

void SetValue(T2 value)

{

this->value = value;

}

T1 GetKey() { return key;}

T2 GetValue() { return value;}

void PrintInfo()

{

cout<<key<<" : "<<value<<endl;

}

};

3 0
2 years ago
Analyze the following code:
olganol [36]

Answer:

The program displays 5 4 3 2 1 and then raises an Array Index Out Of Bounds Exception.

Explanation:

A sample of code output is attached.

The code snippet contain xMethod that takes an array and array length as argument.

In the given snippet, the array {1, 2, 3, 4, 5} and length (5) is passed as argument to the method.

First the method display the element of the array in reverse order

System.out.print(" " + x[length - 1]);

and then the method call itself again. This displays

5 from x[4]

4 from x[3]

3 from x[2]

2 from x[1]

1 from x[0]

but after displaying 1, when it tries to call the method again, an array index out of bound exception is thrown because it will try accessing an element from the array when it is already exhausted.

5 0
3 years ago
3. Which swim_backwards method is called when sammy.swim_backwards() is executed? Why?
Georgia [21]
Classes called child classes or subclasses inherit methods and variables
4 0
3 years ago
Think about a career you would like to have 10 years from now.
WITCHER [35]

Answer: Scientist

Explanation: Scientists use technology to record data, as well as using technology to study different things, for example scientists use computers to track DNA.

6 0
3 years ago
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