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mixas84 [53]
2 years ago
12

Consider an error-free 64 kbps satellite channel used to send 512 byte data frames in one direction, with very short acknowledge

ments coming back the other way. What window size will keep the channel full?
Computers and Technology
1 answer:
Vladimir [108]2 years ago
3 0

Answer:

The answer is "2".

Explanation:

In the given question some information is missing, that is "The propagation time for satellite to earth" which is "270 milliseconds" so, the description to this question can be defined as follows:

Given values:

Bandwidth = 64 kbps

Data frames = 512 bytes  

Propagation Time (t​​​​​​p ) =270 ms

Change Bandwidth  kbps to bps:

1 kb= 1024 bytes

calculated bandwidth= 64 kbps = 64×1024 bps = 65536 bps

1 bytes = 8 bits

512 bytes = 512 × 8 =  4096 bits

Frame length = 4096 bits

Formula

Transmission time (T​​​​​​t) = Frame length /Bandwidth

Window size = 1+2a

where a = Propagation time/Transmission time

Calculate Transmission time:

Transmission time (T​​​​​​t) = 4096 / 65536

Transmission time (T​​​​​​t)= 625 m.sec

Calculate Window size:

Window size = 1+2(270/625)

Window size = 1+2(0.432)

Window size = 1+0.864

Window size = 1.864

Window size = 2

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Answer:

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Explanation:

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Yuliya22 [10]

Answer:

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irina1246 [14]

Answer:

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What is a secondary storage medium that uses magnetic techniques to store and retrieve data on disks or tapes coated with magnet
Elza [17]

Answer:

The correct answer to the following question will be "Magnetic medium".

Explanation:

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1. Add the following method to the Point class:
Pachacha [2.7K]

Answer:

Explanation:

The following code is written in Java and creates all of the methods that were requested in the question. There is no main method in any of these classes so they will have to be called from the main method and call one of the objects created method for the code to be tested. (I have tested it and it is working perfectly.)

class Point {

   private int x, y;

   public void Point(int x, int y) {

       this.x = x;

       this.y = y;

   }

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      double distance = Math.sqrt(Math.pow((other.x - this.x), 2) + Math.pow((other.y - this.y), 2));

      return distance;

   }

   

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           return 1;

       } else if (this.x < 0 && this.y > 0) {

           return 2;

       } else if (this.x < 0 && this.y < 0) {

           return 3;

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       } else {

           return 0;

       }

   }

}

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   char middleInitial;

   

   public String getNormalOrder() {

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   public String getReverseOrder() {

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       return fullName;

   }

}

4 0
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