Answer:
52 tickets cost $10 and 18 tickets cost $12
Step-by-step explanation:
10x+12y=804. (1)
x+y=70. (2)
From (2)
x=70-y
Substitute x=70-y into (1)
10x+12y=804
10(70-y)+12y=804
700-10y+12y=804
700+2y=804
2y=804-700
2y=104
y=104/2
y=52
Recall
x+y=70
x+52=70
x=70-52
x=18
52 tickets cost $10 and 18 tickets cost $12
Answer:
A)3.125hr
B)53.325mi
Step-by-step explanation:
speed=distance/time
an hour and 15min=1.25hr
32/1.25=25.6mi/hr
80/25.6=3.125hr
B)
2hr and 5min=2+5/60=2.083hr
2.083x25.6=53.325mile
Answer:
Minimum percent of the vote that candidate Towne is expected to recieve:
m=51% - 6.3% * 51% =47.787%
Maximum percent of the vote that candidate Towne is expected to recieve:
M=51% + 6.3% * 51% = 54.213%
Solution:
Margin of error: E=6.3%
Minimum percent of the vote that candidate Towne is expected to recieve:
m=51% - E * 51%
m=51% - 6.3% * 51%
m=51% - 51% * 6.3 / 100
m=51% - 3.213%
m=47.787%
Maximum percent of the vote that candidate Towne is expected to recieve:
M=51% + E * 51%
M=51% + 6.3% * 51%
M=51% + 51% * 6.3 / 100
M=51% + 3.213%
M=54.213%
Answer:
$26.02
Step-by-step explanation:
Let the price of a skirt be A and that of coat be B
Iilly bought 6 skirts and 5 coats for a total of $452.62
That’s
6A + 5B = 452.62
Also, Lilly’s sister bought 3 skirts and 5 coats for $289.36
That’s
3A + 5B = 289.36
We now have two equations
1 . 6A + 5B = 452.62
2. 3A + 5B = 289.36
Subtract equation two from equation one
We have
3A = 163.26
Divide both sides by 3
3A/3 = 163.26/3
A = 54.42
A = $54.42
Now substitute 54.42 for A in either equations to get B the price of a coat
Using equation one, we have
6A + 5B = 452.62
6 x 54.42 + 5B = 456.62
326.52 + 5B = 456.62
Subtract 326.52 from both sides
326.52 - 326.52 + 5B = 456.62 - 326.52
5B = 130.1
Divide both sides by 5
5B/5 = 130.1/5
B = 26.02
= $26.02
A coat cost $26.02
