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iogann1982 [59]
3 years ago
15

Suppose you take a class from each of the following four professors: 1, 2, 3, and 4. You write five papers and get the following

grades: 1: A A A A A, 2: D D C B A, 3: A A B C F, 4: D D C D D. Generalizing from Aronson, which professor will you like the most?
Mathematics
1 answer:
harina [27]3 years ago
5 0

Answer:

Professor 1 as he gave the maximum number of A's .

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You worked from 8:30am - 2:15pm with a 12 hour lunch break. How long did you work?
alexandr402 [8]
5.75 if you don’t count the lunch break because I don’t think a lunch break can be twelve hours because it would’nt even be a shift
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3 years ago
4√6 •√3 how do I show work for this because the answer is 2√12​
Yuliya22 [10]

Answer:

4 \sqrt{6}  \times  \sqrt{3}  = 12 \sqrt{2}

Step-by-step explanation:

We want to simplify the radical expression:

4 \sqrt{6}  \times  \sqrt{3}

We write √6 as √(2*3).

This implies that:

4 \sqrt{6}  \times  \sqrt{3}  = 4 \sqrt{2 \times 3}   \times  \sqrt{3}

We now split the radical for √(2*3) to get:

4 \sqrt{6}  \times  \sqrt{3}  = 4 \sqrt{2}  \times  \sqrt{3}  \times  \sqrt{3}

We obtain a perfect square at the far right.

4 \sqrt{6}  \times  \sqrt{3}  = 4 \sqrt{2}  \times  (\sqrt{3} )^{2}

This simplifies to

4 \sqrt{6}  \times  \sqrt{3}  = 4 \sqrt{2}  \times 3

This gives us:

4 \sqrt{6}  \times  \sqrt{3}  = 4 \times 3 \sqrt{2}

and finally, we have:

4 \sqrt{6}  \times  \sqrt{3}  = 12 \sqrt{2}

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3 years ago
I need help with the white sheet and the blue sheet
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