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iogann1982 [59]
3 years ago
15

Suppose you take a class from each of the following four professors: 1, 2, 3, and 4. You write five papers and get the following

grades: 1: A A A A A, 2: D D C B A, 3: A A B C F, 4: D D C D D. Generalizing from Aronson, which professor will you like the most?
Mathematics
1 answer:
harina [27]3 years ago
5 0

Answer:

Professor 1 as he gave the maximum number of A's .

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Ira Lisetskai [31]
Do the unit rate and simplify it and. or make an equation
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3 years ago
Can someone tell me the answers of this if you tell it correctly i will give brainless
nekit [7.7K]

Answer:

0.35

Step-by-step explanation:

I hope its right!!!

  1. use sin (opp/hyp)
  2. Plug in values so: sin45=x/2
  3. Switch the sin45 and x place, they are "equal" in a sense
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7 0
3 years ago
A quadratic function, f(x) = x2 + bx + 9, is such that there is only one real root. Which of the following are possible values o
natita [175]

Answer:

C

Step-by-step explanation:

Remember that we can use the discriminant to determine the amount of roots that a quadratic function has.

If the determinant equals 0, then we only have one real root.

Our function is given by:

f(x)=x^2+bx+9

Then the discriminant will be:

\Delta = b^2-4(1)(9)=b^2-36

We only have one real root, thus our discriminant must be 0:

0=b^2-36

Solve for b:

b^2=36

Thus:

b=\pm 6

The answer is both II and III.

The final answer, then, is C.

7 0
3 years ago
Find the product of 30−−√ and 610−−√. Express it in standard form (i.E., ab√).
Zina [86]

we are given

\sqrt{30} *\sqrt{610}

we can radical formula

\sqrt{a} *\sqrt{b}=\sqrt{a*b}

we get

\sqrt{30} *\sqrt{610}=\sqrt{30*610}

\sqrt{30} *\sqrt{610}=\sqrt{3*61*100}

we can  also write as

\sqrt{30} *\sqrt{610}=\sqrt{100}*\sqrt{3*61}

\sqrt{30} *\sqrt{610}=10\sqrt{183}............Answer


7 0
4 years ago
Read 2 more answers
The given line passes through the points (0, −3) and (2, 3).
Alex

Answer:

The equation would be y + 1 = 3(x + 1)

Step-by-step explanation:

In order to find the equation of this line, we have to use the slope formula to find the slope.

m (slope) = (y2 - y1)/(x2 - x1)

m = (3 - -3)/(2 - 0)

m = (3 + 3)/(2 - 0)

m = 6/2

m = 3

Now that we have that, we can use it along with the second point to put into the point-slope equation.

y - y1 = m(x - x1)

y - -1= 3(x - -1)

y + 1 = 3(x + 1)

6 0
4 years ago
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