Connecticut as a permutation, 1 example would be c1,o,n1,n2,e,c2,t1,I,c3,u,t2. 10 items can form 10! permutations. Considering c1=c2=c3, n1=n2, t1=t2, let’s look at the c all equal condition: 3cs existing one in front of or behind another may form c1, c2, c3; c1, c3, c2; c2,c1,c3… totally 6 different ôkkkiojobvarieties
The first thing you should do is to determine all the zeros, and you will have 7, -11, 2 + 6i, 2 - 6i. After that you have to <span>subtract and (x) from every each zero that you have above, which means </span> <span>And the last step is to multiply them together, and that's all you need! </span> <span>I am pretty sure that everything hase become clear! Regards.</span>