Given: a quadratic function with vertex (2,3) opening upward .
Find: the given statement is true or false.
Explanation: if parabola has a vertex at (2,3) and opens upward, it has one real solution., (2,3) will be a lowest point. The vertex will be at lowest point, it will be minimum.
that means graph has no one real solution. hence it will never going to intersect. so this statement is false.
Final answer: the given statement is FALSE.
Answer:
50 point I want that 50 point pro bro pls man
Answers:
- AE = 26
- AN = 58
- CT = 22.5
- Perimeter of triangle AEN = 127
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Work Shown:
Because points C, P, and T are midpoints of the sides of triangle AEN, this means the segments CP, PT, and CT are midsegments of triangle AEN.
The segment PT = 13 is a midsegment of the larger triangle, and it is parallel to the side AE. Recall the midsegment is half as long as its parallel side.
This means,
PT = (1/2)*AE
2*PT = AE
AE = 2*PT
AE = 2*13
AE = 26
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We'll use the same idea to find AN
CP = (1/2)*AN
2*CP = AN
AN = 2*CP
AN = 2*29
AN = 58
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And we can also say,
CT = (1/2)*EN
CT = (1/2)*43
CT = 22.5
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Add up the sides of triangle AEN to find its perimeter
Perimeter of triangle AEN = (AE)+(EN)+(AN)
Perimeter of triangle AEN = (26)+(43)+(58)
Perimeter of triangle AEN = 127
Answer: E) 1/5
Step-by-step explanation:
The probability of any member being selected for each of the 3 posts is 1/10 that is they have equal probabilities of being selected for any of the posts.
The probability that harry would be selected for;
Secretary Ps= 1/10
Treasurer Pt = 1/10
So the probability of being selected for either secretary or treasurer is
P = Ps + Pt
P = 1/10 + 1/10
P = 2/10
P = 1/5
Note: ignore the sequence of selection
I would say either A or B because -3+3=0 and 0+3=3
Hope this helps
