We have to factor becasue
area=legnth times width
area=4x^2+28x+49
area=(2x+7)(2x+7)
area=(2x+7)^2
legnth =width
we arent' given area so we can't solve
but, , since it is a squaer room, legnth=width so √area=legnth=width
Answer:
Step-by-step explanation:
To define the perpendicular line we need to first know the slope of the reference line graphed.
m=(y2-y1)/(x2-x1) we have points (0,5) and (2,1)
m=(1-5)/(2-0)
m=-4/2
m=-2
For lines to be perpendicular their slopes must satisfy
m1m2=-1, we have a line with a slope of -2 so
-2m=-1
m=1/2, so our perpendicular line is so far
y=x/2+b, it must have point (3,2) so we can solve for b
2=3/2+b
b=1/2, so the swimmer will travel along the line
y=x/2+1/2
Hello!
Let's find the area and see!
A = s^2
A = 3^2
A = 6 ft^2
Now, if you double 3, you get 6. 3 × 2 = 6 Find the area:
A = 6^6
A = 36 ft^2
ANSWER:
No, the area will not be doubled. The area was 9 ft^2 when the sides were 3 feet long. If you double 9, you get 18, since 9 × 2 = 18.
36 is not the double of 9, so no, the area is not double.
Answer:
5A)36 5b)30(mark as brainliest)
Step-by-step explanation:
5a)6+6+6+6+12 = 36
5b)36-8=28
28+2 = 30
