Since you are given that chord AB's length is 8 and is bisected by segment XC, that means segment BC's length is 4 and ∠XCB is a right angle. From there, we use Pythagorean Theorem to solve for length XC:

4² + b² = 5² (Or remember 3-4-5 makes a Pythagorean triple)

c = √(5²-4²)

c = 3

6 0

3 years ago

Which lines are parellele

natali 33 [55]

Line 1 and Line 4 are parallel lines

Solution:

General equation of a line:

y = mx + c

where m is the slope and c is the y-intercept of the line.

<u>To find the slope of each line:</u>

Line 1: $y=-\frac{3}{4} x-6$

Slope $(m_1)=-\frac{3}{4}$

Line 2: $y-7=-4(x+9)$

$y-7=-4x-36$

Add 7 on both sides, we get

$y=-4x-29$

Slope $(m_2)=-4$

Line 3: $y=-2 x+6$

Slope $(m_3)=-2$

Line 4: $x+\frac{4}{3} y=-5$

Subtract x from both sides, we get

$\frac{4}{3} y=-x-5$

Multiply by $\frac{3}{4}$ on both sides, we get

$y=-\frac{3}{4}x-\frac{15}{4}$

Slope $(m_4)=-\frac{3}{4}$

<em>Two lines are parallel, if their slopes are equal.</em>

From the above slopes,

$m_1=m_4$

Therefore Line 1 and Line 4 are parallel lines.

3 0

3 years ago

Bus A and Bus B leave the bus depot at 9 am. Bus A takes 30 minutes to complete its route once and bus B takes 40 minutes to com

kirill [66]

Answer:

11 am

Step-by-step explanation:

Bus A and Bus B leave the bus depot at 9 am.

Bus A takes 30 minutes to complete its route once

Bus B takes 40 minutes to complete its route once.

We solve this finding the Lowest Common Multiple of the minutes each bus uses to complete it's route

30 = 3 × 10

40 = 4 × 10

= 3 × 4 × 10

= 120 minutes

120 minutes after 9 am is

60 minutes = 1 hour

= 2 hours.

9am + 2 hours

= 11 am.

Therefore, they be back at the bus depot together at 11 am

4 0

4 years ago