Step-by-step Answer:
There is a total of 10 coins, 5 dimes, 2 quarters and three pennies.
By picking a coin, it could be any that shows up out of the 10, so the probability of picking any coin in particular is 1 / 10.
If there are 5 dimes, the probability of picking ANY one particular dime is 1/10, so with 5, the probability of picking ANY of the five dimes is 5/10 = 1/2.
Going along the same line of thought, the probability of picking any of quarters and pennies would be 2/10+3/10 = 5/10 = 1/2 as well.
The answer for the problem is -13x+8
Answer:
<u>If A and B are independent events, P(A and B) = P (A) * P (B)</u>
Step-by-step explanation:
Let's recall that independent events means that when one event occurs, it has no impact or influence on the probability of another event occurring. Here’s an example. Let’s say that we have two events, A and B.
Event A : it rains in Seattle
Event B : the Super Bowl match is cancelled in Miami
The two events are independent; if it rains in Seattle, this will have no impact on the probability that the Super Bowl match is cancelled in Miami. Raining in Seattle and the cancellation of the Super Bowl are independent events, therefore:
<u>P(A and B) = P (A) * P (B)</u>
