The probability that the transistor will last between 12 and 24 weeks is 0.424
X= lifetime of the transistor in weeks E(X)= 24 weeks
O,= 12 weeks
The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.
X~gamma(
)
E(X)= 
= 
=6 weeks
V(x)= 
=24/6= 4
Now we can find the solutions:
The excel formula used to create Figure one is as follows:
=gammadist(X, , , False)
P(
)
P(
)
P(
)
P= 0.424
Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424
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Answer: The new ratio will be 1/4
Explanation: The initial ratio of losses to wins is 3 to 2. If we sum the numer of losses and wins 3 + 2 = 5 games, that means they loss 3 out of 5 games , and they win 2 out of 5 games.
So if they had won twice as many of the games, that is 2*2=4. And since the number of games is the same ( 5 ), then they would have won 4 games and loss only 1.
So the new ratio of losses to wins will be 1 to 4, or expressed in a fraction: 1/4
Answer:
b
Step-by-step explanation:
I mean I believe its b it looks like theres three
Answer:
(1;-2)
Step-by-step explanation:
x=-2y-3
2(2y+3)=-6y-9-5
10y=-20
y=-2
x=4-3=1
Answer:
74-25 is 49
Step-by-step explanation:
