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marin [14]
3 years ago
14

If 5 sweaters cost $43.60. how much would 7 sweaters cost?

Mathematics
1 answer:
ivanzaharov [21]3 years ago
7 0
Hi there!

To find this out, divide 43.60 by 5 to find the single cost..

43.60 / 5 = 8.72.

1 sweater is $8.72

Multiply 8.72 by 7 to find the cost of 7 sweaters.

8.72 * 7 = 61.04.

7 sweaters cost $61.04.

Hope this helps! ☺♥
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2

Step-by-step explanation:

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3 years ago
Read 2 more answers
No copy and paste answers.
miss Akunina [59]

Answer:

  2.5 miles

Step-by-step explanation:

The relation between time, speed, and distance is ...

  distance = speed × time

We can define t to be Stanley's swimming time. Then t+0.5 was his running time, and 2(t+0.5) was his biking time. His total distance covered is ...

  64 = 9(t +0.5) +16(2(t +0.5)) +2.5(t)

  64 = 43.5t +20.5 . . . . . . . simplify

  43.5 = 43.5t . . . . . . . . . subtract 20.5

  t = 1 . . . . . . . . . . . . . . divide by the coefficient of t

Stanley swam for 1 hour, so the distance he covered while swimming was ...

  (2.5 mi/h)(1 h) = 2.5 mi

Stanley covered 2.5 miles while swimming.

_____

<em>Additional comment</em>

Stanley ran for 1.5 hours, covering 9×1.5 = 13.5 miles. He biked for 3 hours, covering 16×3 = 48 miles. His total distance was 2.5 +13.5 +48 = 64 miles, as given.

6 0
2 years ago
How do u do #10? Plz show on paper
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Reflection across the line y=x simply swaps the x and y coordinates.
K'(-2, -5), A'(1, -4), I'(-1, 0), J'(-4, -2)

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3 years ago
Which of the following equations is equivalent to 36 – 2 = 34?
JulsSmile [24]

Answer: 34 + 2 = 36

Step-by-step explanation:

36 - 2 = 34

Add 2 to this:

36 - 2 + 2 = 34 + 2

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7 0
3 years ago
Hree people play a game in which one person loses and two people win each round. The loser must pay each winner the amount that
ipn [44]

Answer:

$7 ; $4 ; $3

Step-by-step explanation:

Given that:

1 player loses and 2 wins

Loser pays each winner amount each winner already has

3 rounds was played

At the end, each player has lost 1 round each and has $8.00

Since each player lost 1 round each, then each player won twice.

Given that the players are A, B and C

Starting from the last round :

Recall; they all have $8 after the last round.

If A lost the last round and pays B and C the amount they already have.

B and C finally have $8, Hence amount A paid B and C = 8/2 = $4 each

Hence, at the end of 2nd round / before last round :

A has ($8 paid + $8 final) = $16

B and C each have $4

End of first round before 2nd round of game:

If B lost, and pays A and C the amount they already have ;

A finally has 16 hence, amount B pays A = 16/2 = $8

Amount B pays C = 4/2 = $2

A = $8

B = $4 + $(8 + 2) = $14

C = $2

Ist round

C will lose :

Amount C pays B = $14 / 2 = $7

Amount C pays A = $8 /2 = $4

Hence, amount C has before round 1:

$7 + $4 + $2 = $13

Hence; Before the game ;

Either of the three players have ;

$7 ; $4 and $13

6 0
2 years ago
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