9(8d-5)+13=12d-2 find a solution for d

A local University accepted 2,300 students out of 4,500 applicants for admission. What was the acceptance rate, expressed as a p

Mademuasel [1]

2300 out of 4500 were chosen

2300 / 4500 = 0.5111

0.51 = 51%

51% is the acceptance rate.

4 0

3 years ago

Read 2 more answers

How do i do these fractions by 1/2?

Svetlanka [38]

I need to see the directions

4 0

3 years ago

I’m still confused on how to work the percentages

Serjik [45]

Answer:

13 is your answer

Step-by-step explanation:

it's the biggest number and more students like cats

Hope this helps

God bless you

Have a great day

- Kayla :)

5 0

3 years ago

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2. What is the variable in the expression: 13x3 +7 (Select one answer) 7 3 13

sdas [7]

I think it would be 3

3 0

3 years ago

Assume that a company sold 5.75 million motorcycles and 3.5 million cars in the year 2010. The growth in the sale of motorcycles

OverLord2011 [107]

Answer:

Final answer is approx 6.644 years.

Step-by-step explanation:

Given that a company sold 5.75 million motorcycles and 3.5 million cars in the year 2010. The growth in the sale of motorcycles is 16% every year and that of cars is 25% every year.

So we can use growth formula:

$A=P\left(1+r\right)^t$

Then we get equation for motorcycles and cars as:

$A=5.75\left(1+0.16\right)^t$

$A=3.5\left(1+0.25\right)^t$

Now we need to find about when the sale of cars will be more than the sale of motorcycles. So we get:

$3.5\left(1+0.25\right)^t>5.75\left(1+0.16\right)^t$

$3.5\left(1.25\right)^t>5.75\left(1.16\right)^t$

$\frac{\left(1.25\right)^t}{\left(1.16\right)^t}>\frac{5.75}{3.5}$

$\left(\frac{1.25}{1.16}\right)^t>1.64285714286$

$t\cdot\ln\left(\frac{1.25}{1.16}\right)>\ln\left(1.64285714286\right)$

$t>\frac{\ln\left(1.64285714286\right)}{\ln\left(\frac{1.25}{1.16}\right)}$

$t>6.6436473051$

Hence final answer is approx 6.644 years.

7 0

3 years ago