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enyata [817]
3 years ago
5

He vertices of ?ABC are A(2, 8), B(16, 2), and C(6, 2). The perimeter of ?ABC is units, and its area is square units.

Mathematics
2 answers:
iogann1982 [59]3 years ago
8 0

Answer:

Note :

The perimeter is :  AB + BC + CA


AB =√((XB - XA)² + (YB - YA)²) = √((16-2)²+(2-8)²) = √(12²+6²) = √(144+36)=√180

AB = √(36×5) = 6√5 units

same method for :  BC ; CA   ..........


katovenus [111]3 years ago
6 0

Answer:

Perimeter = 32.44 unit

Area of triangle = 30 unit²

Step-by-step explanation:

By distance formula distance between (a,b) and (c,d) is \sqrt{(c-a)^2+(d-b)^2}

So, we have

      AB=\sqrt{(16-2)^2+(2-8)^2}=15.23\\\\BC=\sqrt{(16-6)^2+(2-2)^2}=10\\\\AC=\sqrt{(2-6)^2+(8-2)^2}=7.21

Perimeter = 15.23 + 10 + 7.21 = 32.44 unit

We have s=\frac{15.23+10+7.21}{2}=16.22

Area of triangle=\sqrt{s(s-AB)(s-BC)(s-AC)}=\sqrt{16.22(16.22-15.23)(16.22-10)(16.22-7.21)}=30

Area of triangle = 30 unit²

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Answer:

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7 0
3 years ago
Read 2 more answers
Why do you have to show your work
swat32
In order to help explain how you came to your answer. It also helps when marking or reviewing because it's easier to find any mistakes
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