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Wewaii [24]
3 years ago
12

5. Consider a cylindrical flowerpot with a radius 6 cm and a height of 11.5 cm. Calculate the lateral surface area of the painte

d pot.
Mathematics
1 answer:
Nina [5.8K]3 years ago
8 0

Answer: 660 cm²

Step-by-step explanation:

Surface area of a cylinder = 2πr² ± 2πrh = 2πr ( r + h )

π = 22/7

r = 6 cm

h = 11.5 cm

Lateral surface area = 2 x 22/7 x 6 ( 6 + 11.5 )

= 660 cm²

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The area of a rectangular garden can be expressed as A = 2x^2 -x -6. The width of the garden is 2x+3. Find an expression for the
zalisa [80]

Answer:

Step-by-step explanation:

2x² -x - 6 = 2x² - 4x + 3x - 3*2

              = 2x*(x - 2) + 3*(x - 2)

              = (x-2)(2x + 3)

A = 2x² -x - 6

A = (x - 2)(2x + 3)

length*width = (x - 2)(2x + 3)

length * (2x +3) = (x - 2)(2x + 3)

length=\frac{(x-2)(2x+3)}{(2x+3)}

length = x - 2

5 0
3 years ago
On a bicycle trail, the city is painting arrows like the one shown below: Upper pointing arrow with height of 11 and length of 9
Studentka2010 [4]

The image of the arrow is missing, so i have attached it.

Answer:

A_t = 69.5 cm²

Step-by-step explanation:

In a second image attached, I have divided the arrow into triangle and rectangle.

From the second image,

A1 is area of triangle while A2 is area of rectangle

Area of triangle is; A1 = ½bh

Our triangle base is given as 9 cm.

To get the height, we will subtract the rectangle height of 8 cm from the total arrow height.

Thus; height of triangle; h = 11 - 8 = 3cm

Thus;

A1 = ½ × 9 × 3

A1 = 13.5 cm²

Formula for area of rectangle is;

A2 = length × breadth

A2 = 8 × 7

A2 = 56 cm²

Thus, total area of arrow is;

A_t = A1 + A2 = 13.5 + 56

A_t = 69.5 cm²

8 0
2 years ago
Solve the problem using the guess-and-check method.
ehidna [41]
Answer is 14 lightbulbs
8 0
2 years ago
Find a Cartesian equation for the curve and identify it. r=8tanxsecx
ANTONII [103]
R = 8 tan(x) sec(x)

In order to solve this, we are going to use the following:
r = sqrt(x^2 + y^2) //but in this case, we don't need this.
tan(x) = Y / X
X = r cos(x)
Y = r sin(x)

<span>(r cos x)^2 = 8(r sin x)</span>

x^2 = 8y
3 0
3 years ago
There were 6 purple socks and 4 oraange socks without looking and then another without looking (or replacing the first). What is
shusha [124]

Answer:

The probability that he picked 2 purpled socks is <u>0.33</u>.

Step-by-step explanation:

Given:

Number of purple socks, n(P) = 6

Number of orange socks, n(O) = 4

Two socks are picked without replacement.

Now, total number of socks, n(T)=N(P)+n(O)=6+4=10

Probability of picking the first cap as purple cap is given as:

P(P1)=\frac{n(P)}{n(T)}\\\\P(P1)=\frac{6}{10}=\frac{3}{5}

Since there is no replacement, the number of socks decreases by 1. Also, if the first sock picked is purple, then number of purple socks is also decreased by 1.

Therefore, probability of picking the second cap as purple cap is given as:

P(P2)=\frac{n(P)-1}{n(T)-1}\\\\P(P2)=\frac{5}{9}

Now, probability that both the picked caps are purple is given by their probability product. This gives,

P(P1\ and\ P2)=P(P1)\times P(P2)\\\\P(P1\ and\ P2)=\frac{3}{5}\times\frac{5}{9}\\\\P(P1\ and\ P2)=\frac{3}{9}=\frac{1}{3}=0.33

Therefore, the probability that he picked 2 purpled socks is 0.33

4 0
3 years ago
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