4 years ago

What is the answer????

1 answer:

3 0

No, because there is no number between 0 and 1.

I think thats the answer but im not sure

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devlian [24]

Hello,
$f(1)=2\\
f(2)= \dfrac{2}{5} =2*5^{-1}\\
f(3)= \dfrac{2}{25} =2*5^{-2}\\
f(4)= \dfrac{2}{125} =2*5^{-3}\\\\

\boxed{f(x)= 2*5^{-x}} \\


$

4 0

3 years ago

natta225 [31]

$(x-2)(x^2+1)=x^3+x-2x^2-2=x^3-2x^2+x-2$

5 0

3 years ago

xeze [42]

The answer to the question is 6/9.

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3 years ago

In-s [12.5K]

Given the piecewise function:

$f(x)=\begin{cases}{3\text{ if -2}\leq x$

Let's select the graph which represents the function.

We have the graph below:

For f(x) = 3, the graph will be a horizontal line on y = 3 which has an open dot on x = 0 and a closed dot on x = -2

For f(x) = 1 if x = 0, the graph will have a closed dot located on the point (0, 1)

For f(x) = -(x + 1) if 0 < x ≤2, the graph will have a negative slope with an open dot on (0, -1) and closed dot on (2, -3)

ANSWER:

Graph B

8 0

1 year ago

Andrews [41]

If it is less then 5 you do the next hundred down 5 and above the next one up

8 0

3 years ago