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tester [92]
3 years ago
12

PLEASE HELP ME SOMEONE. How do I do this? Please explain and I will give you crown.

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
8 0

Answer: the one in the bottom right

Step-by-step explanation: each month which is the x axis ( the bottom line) the y axis (line on the left) goes up by 5

so when the x axis is 1 the y axis should be at 5

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Hello there,
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andrew11 [14]
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What is the coefficient of y in 2-5y÷2​
Setler [38]

Answer:

-5/2 because there is -5y/2 but we have to take coefficient only so -5/2

5 0
3 years ago
Solve the equation.
Levart [38]

Answer:

x=34

Step-by-step explanation:

6 - ( x-7) ^ 1/3 = 3

Subtract 6 from each side

6-6 - ( x-7) ^ 1/3 = 3-6

- ( x-7) ^ 1/3 = -3

Divide each side by a negative

 ( x-7) ^ 1/3 = 3

Cube each side

 ( x-7) ^ 1/3 ^3 = (3)^3

x-7 = 27

Add 7 to each side

x-7+7 = 27+7

x = 34

Check

6 - ( 34-7) ^ 1/3 = 3

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Good solution

8 0
4 years ago
Consider the quadratic equation ax^2+bx+5=0,where a, b and c are rational numbers and the quadratic has two distinct zeros.
FrozenT [24]
You have shared the situation (problem), except for the directions:  What are you supposed to do here?  I can only make a educated guesses.  See below:

Note that if    <span>ax^2+bx+5=0    then it appears that c = 5 (a rational number).

Note that for simplicity's sake, we need to assume that the "two distinct zeros" are real numbers, not imaginary or complex numbers.  If this is the case, then the discriminant,    b^2 - 4(a)(c), must be positive.  Since c = 5, 

b^2 - 4(a)(5) > 0, or b^2 - 20a > 0.

Note that if the quadratic has two distinct zeros, which we'll call "d" and "e," then 

(x-d) and (x-e) are factors of ax^2 + bx + 5 = 0, and that because of this fact,

         - b plus sqrt( b^2 - 20a )
d =  ------------------------------------
                      2a

and

 </span>         - b minus sqrt( b^2 - 20a )
e =  ------------------------------------
                      2a

Some (or perhaps all) of these facts may help us find the values of "a" and "b."  Before going into that, however, I'm asking you to share the rest of the problem statement.  What, specificallyi, were you asked to do here?

7 0
3 years ago
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