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3 years ago

PLEASE HELP ME SOMEONE. How do I do this? Please explain and I will give you crown.

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

8 0

Answer: the one in the bottom right

Step-by-step explanation: each month which is the x axis ( the bottom line) the y axis (line on the left) goes up by 5

so when the x axis is 1 the y axis should be at 5

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In STU, SU =18 and TU =13. Find m

erastova [34]

Answer:

m=22.2

Step-by-step explanation:

By using the Pythagorean’s theorem i.e

hypotenuse^2=opposite^2+adjacent^2

Where

Hypotenuse =unknown

Opposite =18

Adjacent =13

Hyp^2=18^2+13^2

Hyp^2=324+169

Hyp^2=493

Hyp=sqrt 493

Hyp=m=22.2

3 0

3 years ago

For what values of y : is the value of the binomial 5y−1 greater than the value of the fraction 3y−1/4

VashaNatasha [74]

Answer:

y>0.375

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Hi, can someone please help, and possibly explain the answer please.

mr_godi [17]

Answer:

$x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}$

Step-by-step explanation:

Quadratic formula: $x=\frac{-b\±\sqrt{b^2-4ac} }{2a}$ when the equation is $0=ax^2+bx+c$

The given equation is $1=-2x+3x^2+1$ . Let's first arrange this so its format looks like $y=ax^2+bx+c$ :

$1=-2x+3x^2+1$

$1=3x^2-2x+1$

Subtract 1 from both sides of the equation

$1-1=3x^2-2x+1-1\\0=3x^2-2x+0$

Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:

$x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}$

I hope this helps!

8 0

2 years ago

Please please come help me please

tatiyna

2/10 x 2/10 = 4/10 that can be a expression sorry if im wrong

7 0

3 years ago

Read 2 more answers

1/secA-tanA - 1 /secA+tanA <br>So the answer comes 2tanA/sec^2 A-tan^2A <br>how ??.

solniwko [45]

Answer:

Hope it helps

thanks ।।।।।।।।।।।।।

7 0

2 years ago