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3 years ago

What are the signs of the x- and y-coordinates of points within each of the four quadrants in the coordinate plane?

Mathematics

2 answers:

Vladimir79 [104]3 years ago

8 0

Q1: +,-
Q2: +,-
Q3: -,-
Q4: -,+

Kitty [74]3 years ago

7 0

Quartile 1: (+,-)
Quartile 2: (+,-)
Quartile 3: (-,-)
Quartile 4: (-,+)

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tres hermanos danvueltas circuito en bicicleta. el mayor tarda 18 en dar Una vuelta el del medio 24 minutos yel menos 36 minutos

hodyreva [135]

Tienes que hallar el mínimo común múltiplo de las 3 cantidades.

18= 2×3²
24= 2³×3
36= 2²×3²

mcm(18,24,36) = 2³×3²=8×9= 72

Eso quier decir que si partieron a la misma hora se encontraran de nuevo en el punto de partida 72 minutos después de la salida.

Las vueltas que habrán realizado será el resultado de dividir 72 entre el tiempo que tardan en dar una vuelta

Mayor: = 4

Mediano: = 3

Pequeño: = 2

Soluciónes:

se vuelven a encontrar a los 72 min de la salida
El mayor dió 4 vueltas, el mediano 3 y el pequeño 2

6 0

2 years ago

H=-16t^2+368

elixir [45]

The vertex and the t-intercept where t>0, will help solve this problem. Sending the work on the attachment.

5 0

3 years ago

Simplify the expression -2x^2(4x − 3). -8x3 − 6x2 -8x3 + 6x2 8x3 − 6x2 8x3 + 6x2

Digiron [165]

To simplify the expression we are going to use the distributive property of multiplication: $a(b+c)=ab+ac$ .
We can infer from our problem that $a=-2x^2$ , $b=4x$ , and $c=-3$ . So lets apply the property to simplify our expression:
$-2x^2(4x-3)=(-2x^2)(4x)+(-2x^2)(-3)$
$(-2x^2)(4x)+(-2x^2)(-3)=-8x^3+6x^2$

We can conclude that the correct answer is -8x3 + 6x2

8 0

3 years ago

When a scientist conducted a genetics experiments with peas, one sample of offspring consisted of 943 peas, with 717 of them hav

pshichka [43]

Using the normal approximation to the binomial distribution, it is found that:

a) 0.242 = 24.2% probability of getting 717 or more peas with red flowers.

b) Since Z < 2, 717 peas with red flowers is not significantly high.

c) Since 717 peas with red flowers is not a significantly high result, we cannot conclude that the scientist's assumption is wrong.

For each pea, there are only two possible outcomes. Either they have a red flower, or they do not. The probability of a pea having a red flower is independent of any other pea, which means that the binomial distribution is used to solve this question.

Binomial distribution:

Probability of x successes on n trials, with p probability.

Normal distribution:

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

If Z > 2, the result is considered significantly high.

If $np \geq 10$ and $n(1-p) \geq 10$ , the binomial distribution can be approximated to the normal with:

$\mu = np$

$\sigma = \sqrt{np(1-p)}$

In this problem:

943 peas, thus, $n = 943$
3/4 probability of being red, thus $p = \frac{3}{4} = 0.75$ .

Applying the approximation:

$\mu = np = 943(0.75) = 707.25$

$\sigma = \sqrt{np(1-p)} = \sqrt{943(0.75)(0.25)} = 13.297$

Item a:

Using continuity correction, this probability is $P(X \geq 717 - 0.5) = P(X \geq 716.5)$ , which is 1 subtracted by the p-value of Z when X = 716.5.

Then:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{716.5 - 707.25}{13.297}$

$Z = 0.7$

$Z = 0.7$ has a p-value of 0.758.

1 - 0.758 = 0.242

0.242 = 24.2% probability of getting 717 or more peas with red flowers.

Item b:

Since Z < 2, 717 peas with red flowers is not significantly high.

Item c:

Since 717 peas with red flowers is not a significantly high result, we cannot conclude that the scientist's assumption is wrong.

A similar problem is given at brainly.com/question/25212369

6 0

2 years ago

Help plz:))) I’ll mark you BRAINLIEST

Virty [35]

Answer:

If i'm not mistaken X=3 and Y=16

hope his helps

5 0

3 years ago