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xxTIMURxx [149]
3 years ago
5

Are you supposed to put a period at the end of a verbal expression in algebra?

Mathematics
1 answer:
ivann1987 [24]3 years ago
6 0
Nope :) hope this helps!
You might be interested in
Please refer to the following attachment and find the value of x.
Drupady [299]

Answer:

5

Step-by-step explanation:

Sum of interior angles in a 4 sided quadrilateral is 360,

110 + 70 + 14x + 23x - 5 = 360

180 + 37x - 5 = 360

180 - 5 + 37x = 360

175 + 37x = 360

37x = 360 - 175

37x = 185

x = 185 / 37

x = 5

7 0
2 years ago
Read 2 more answers
Mr. Pettit asks you to jog around the perimeter of the gym 3 times. The length of the gym is 65 1/2 feet and the width is 32 1/4
Ilia_Sergeevich [38]

Answer:

586.5 ft.

Step-by-step explanation:

Find the Perimeter of the gym which is a rectangle. Formula is 2 (L+W) so,

2(65.5+32.25) = 195.5ft then multiply by 3 times around the perimter of the gym

(195.5 x3= 586.5 ft)

4 0
3 years ago
Two equations are given below:
stealth61 [152]

a is given to us so just plug a into the first equation:

b-3 - 3b =9

Add 3 to both sides:

b-3b=12

Combine like terms:

-2b=12

Divide by -2 to get b by itself:

b=-6

The only answer with b as -6 is the first one, (-9,-6)

8 0
3 years ago
Read 2 more answers
1. The ordered pair (-1, -1) is a solution of the system -4x + 2y = 2 and x + y = -2.
Nastasia [14]
1: (-1,-1) is (x, y) to see if it is a solution, you would just plug in x and y and see if the equation is true.
-4 (-1) + 2(-1) = 2
4 + -2 = 2
2 = 2 CORRECT
So... plug in x and y in the second equation to Make sure it works for that one too.
-1 + -1 = -2
-2 = -2 CORRECT
So, yes. (-1,-1) is a solution to both equations.
5 0
3 years ago
9.4 The heights of a random sample of 50 college stu- dents showed a mean of 174.5 centimeters and a stan- dard deviation of 6.9
gladu [14]

Answer:  a) (176.76,172.24), b) 0.976.

Step-by-step explanation:

Since we have given that

Mean height  = 174.5 cm

Standard deviation = 6.9 cm

n = 50

we need to find the 98% confidence interval.

So, z = 2.326

(a) Construct a 98% confidence interval for the mean height of all college students.

x\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=(174.5\pm 2.326\times \dfrac{6.9}{\sqrt{50}})\\\\=(174.5+2.26,174.5-2.26)\\\\=(176.76,172.24)

(b) What can we assert with 98% confidence about the possible size of our error if we estimate the mean height of all college students to be 174.5 centime- ters?

Error would be

\dfrac{\sigma}{\sqrt{n}}\\\\=\dfrac{6.9}{\sqrt{50}}\\\\=0.976

Hence, a) (176.76,172.24), b) 0.976.

8 0
3 years ago
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