The first false statement in the proof as it stands is in Line 5, where it is claimed that a line of length 2.83 is congruent to a line of length 4.47. This mistake cannot be corrected by adding lines to the proof.
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The first erroneous tactical move is in Line 4, where the length of DE is computed, rather than the length of FD. This mistake can be corrected by adding lines to the proof.
A correct SAS proof would use segment FD in Line 4, so it could be argued that the first mistake is there.
Answer:
Step-by-step explanation:
(N)0.05 + (17-N)0.1 = M; M = amount of money I have.
Or 1.7-0.05N = M.
Answer:
The asnwer i fro 5/2 iss 2.5 and the other question is the answer is 1.3 is we add now is 3.8
Step-by-step explanation:
Yes because the median and range are not a function of the totality of the sample set, the median is just value that is halfway of the set and the range is the difference of the highest and lowest value. As long as the lowest and highest value and the halfway value are the same in each set, the median and range will be equal no matter what the other values of the set are.
What is the given matrix?
you didn't show a matrix.
the components of the matrix are the elements.
and the elements of the inverse matrix are the elements of the inverse matrix
1)
so if matrix A is 1 4 1
2 5 2
3 6 3
2)
14114
25225
36336
3)
15 24 12
15 12 24
4)
[A]=(15+24+12=51)-(15+12+24=51)
[A]=0
5)
52 23 25
63 23 36
41 11 14
63 33 36
41 12 14
52 12 25
6)
15-12 6-6 12-15
12-6 3-3 6-12
8-5 2-2 5-8
7)
3 0 -3
6 0 -6
3 0 -3
8)
(+)3 (-)0 (+)-3
(-)6 (+)0 (-)-6
(+)3 (-)0 (+)-3
=
3 0 -3
-6 0 6
3 0 -3
9)
3 -6 3
N= 0 0 0
-3 6 -3
10) the inverse of [A]= 1/|A|*[N]
which is in this case ⁻A= 0
because |A|=0
