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velikii [3]
3 years ago
9

Logarithmic and Exponential Forms of Equations In Exercise,Write the logarithmic equation as an exponential equation,or vice ver

sa.
e0.25 = 1.2840...
Mathematics
1 answer:
GenaCL600 [577]3 years ago
8 0

Answer:

0.25 = ln(1.284025417)

Step-by-step explanation:

For this case we have the following equation:

e^{0.25} = 1.284025417

We need to remember that the base for the natural log is the euler number e = 2.718281818 , and log_{e} = ln

And we want to write this expression as a logarithmic equation so we ust need lo apply natural log on both sides and we got:

ln e^{0.25} = ln(1.284025417)

And since the natural log and the exponetiation are inverse operations w have the identity operator in the left part of the equation and we got:

0.25 = ln(1.284025417)

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Note that Range = Max – Min.
In this case, Max = 452452, Min = 221221.
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