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velikii [3]
3 years ago
9

Logarithmic and Exponential Forms of Equations In Exercise,Write the logarithmic equation as an exponential equation,or vice ver

sa.
e0.25 = 1.2840...
Mathematics
1 answer:
GenaCL600 [577]3 years ago
8 0

Answer:

0.25 = ln(1.284025417)

Step-by-step explanation:

For this case we have the following equation:

e^{0.25} = 1.284025417

We need to remember that the base for the natural log is the euler number e = 2.718281818 , and log_{e} = ln

And we want to write this expression as a logarithmic equation so we ust need lo apply natural log on both sides and we got:

ln e^{0.25} = ln(1.284025417)

And since the natural log and the exponetiation are inverse operations w have the identity operator in the left part of the equation and we got:

0.25 = ln(1.284025417)

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5/8 +1/2 in lowest terms
Rufina [12.5K]

Answer:

9/8 or 1 1/8

Step-by-step explanation:

5/8 +1/2

5/8+ 4/8 = 9/8 or 1 1/8

4 0
3 years ago
Someone please help! Im in a hurry !!
jeka94

Answer:

wouldnt it be c

Step-by-step explanation:

8 0
3 years ago
It is 18 degrees Celsius at 8 am, and 14 degrees Celsius by noon. The change in the temperature from 8am to noon is?
Oliga [24]

Answer:

4 degrees Celsius

Step-by-step explanation:

It is asking for the change in temperature, or the difference. In word problems like this it is asking for subtraction.

So you just need to subtract the temperature at noon from the temperature at 8 am.

18 - 14 = 4 degrees

8 0
3 years ago
Read 2 more answers
Explain why (–4x)0 = 1, but –4x0 = –4.
hodyreva [135]
Any number raised to power of 0 is 1.
In (-4x)^0, because of the parenthesis, the whole number is being raided to 0, which gives 1.
But in -4x^0, only x is being raised to 0, thus -4x^0 = -4(1) = -4.
5 0
3 years ago
Geometry math question no Guessing and Please show work thank you
algol [13]

AD is perpendicular to BC, therefore from the slope m₁ of BC and the slope m₂ of AD we have equation:

m_1m_2=-1 (*)

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have

B(7,\ -2)\to x_1=7,\ y_1=-2\\C(3,\ 8)\to x_2=3,\ y_2=8

Substitute:

m_1=\dfrac{8-(-2)}{3-7}=\dfrac{10}{-4}=-\dfrac{5}{2}

Substitute to the equation (*):

-\dfrac{5}{2}m_2=-1\ \ \ |\cdot\left(-\dfrac{2}{5}\right)\\\\m_2=\dfrac{2}{5}

Answer: D. 2/5

7 0
4 years ago
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