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e-lub [12.9K]
3 years ago
10

A voltage of 50 V appears across a 20-μF capacitor.

Business
1 answer:
AlekseyPX3 years ago
3 0

Answer:

a. 1nC

b. 0C

Explanation:

Net charge q stored on plate of capacitor is

q = CV

Where C = 2uF = 2 x 10^-6F

V= 50v

q = 20 x 10^-6 x 50 = 1000 x 10^-6 = 1000uF = 10^-9 = 1nC

b. the total net charge on another plate is equal in absolute value to the first one, but it is charged with opposite Pole so always is valid that total net charge on both plates are equal to zero.

That's the other charge on the plate is -1nc

1 nC + -1nC = 0C

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