Question

a) Determine a minimum inventory production plan (i.e., one that allows arbitrary hiring and firing). b) Determine the production plan that meets demand but does not hire or fire workers during the six-month period. c) Let’s say subcontracting is allowed. Let’s say we implement the constant workforce with subcontracting plan, what would the cost of subcontracting need to be to beat the cheaper of the two options above? d) Using this subcontracting cost of $50, formulate a LP and solve to optimality for the constraints of this problem

Answer 1

Answer:

Hello your question is incomplete attached below is the complete question

answer:

A) 32 units ( number of units per month per worker )

B) number of workers required = 975 / 32 ≈ 31

c) mean of the two values = 138 + 41 ) / 2 = $89.50

Explanation:

A) Determine a minimum inventory production plan ( i.e. one that allows arbitrary hiring and firing )

The number of units per month per worker = 32 units

To have a minimum/least inventory; production plan  = demand by hiring or firing

of employees

attached below is the table

B)  determine the production plan that meets demand but does not hire or fire workers during the six-month period

To determine this production plan we have to find the per month production = (Total demand - beginning inventory ) / 6

                   = ( 6350 - 500 ) / 6  = 975 units produced

number of workers required = 975 / 32 ≈ 31

C) Calculate The cost of subcontracting needed to beat the cheaper of the two options above

regular cost = 8 * 5 = $40

we will keep 30 workers in order to determine how much subcontracting is needed and the maximum and minimum value of each unit is kept hence the overall cost <  $253900.

if subcontracting cost = $138  then total cost = $253820

If subcontracting cost = $41  then total cost = $245090.

Therefore mean of the two values = 138 + 41 ) / 2 = $89.50

D) subcontracting cost of $50 formulating a LP and solve to optimality for the constraints of this problem

Z <= (Y+1)*7680 , X + 32Y >= 5850