A rectangular billboard image is 5 ft wide and 4 ft high. If the available billboard space is 25 ft by 15 ft, what are the dimen
sions of the largest image that can fit into the space? someone help please
1 answer:
Answer:
18¾ ft × 15 ft
Step-by-step explanation:
The dimensions of the billboard are 25 ft by 15 ft.
The dimensions of the image are 5 ft by 4 ft
Case 1.<em> Expand the length of the image to 25 ft. </em>
We have multiplied the length by five, so we must multiply the width by five.
w = 5 × 4 = 20 ft. That's too big. The image will overflow the billboard
by 5 ft.
<em>Case 2. </em><em>Expand the width of the image to 15 ft. </em>
We have multiplied the width by 15/4, so we must multiply the length by 15/4.
l = 15/4 × 5 = 75/4 = . That will fit, with 6¼ ft left over.
The expanded image will be 18¾ ft × 15 ft.
In the image below, the big rectangle represents the billboard, and the red rectangle represents the original image.
The pink rectangle represents the dilation of the original image to a width of 15 ft.
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Answer:
Step-by-step explanation:
The formula for a circle of radius r centered at (h, k) is ...
(x -h)^2 +(y -k)^2 = r^2
Both of the given points are on the line y=-1. The distance between them is the difference of their x-coordinates, 2 -(-2) = 4. So, the radius of the circle is 4 and the equation becomes ...
(x -2)^2 +(y -(-1))^2 = 4^2
(x -2)^2 +(y +1)^2 = 16 . . . . . . . . . matches choice A
