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3 years ago

PLEASE HURRY~ CHOOSING BRAINLIEST

Mathematics

2 answers:

olya-2409 [2.1K]3 years ago

8 0

C because y=mxb so plug in the numbers

svp [43]3 years ago

6 0

Answer:

Step-by-step explanation:

Because the y intercept is two our y=mx+b equation looks like this

y=mx+2

We then need to find a slope that gives us an x intercept of 3 or satisfies the coordinates of (3,0)

We can plug this in and solve

0=3m+2

-2=3m

-2/3=m

which means our final equation is

-2/3x+2

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There were 516 tickets sold for a basketball game. The activity cardholder tickets cost 1.25 and the non ticket holders ticket w

xxTIMURxx [149]

Answer:

card holder ticket was 807 and non holder is 403.5 (rounded up) is 403.50. Have a nice day.

3 0

3 years ago

A pharmaceutical company proposes a new drug treatment for alleviating symptoms of PMS (premenstrual syndrome). In the first sta

Akimi4 [234]

Answer:

95% confidence interval for p, the true proportion of all women who will find success with this new treatment is [0.238 , 0.762].

Step-by-step explanation:

We are given that a pharmaceutical company proposes a new drug treatment for alleviating symptoms of PMS (premenstrual syndrome).

In the first stages of a clinical trial, it was successful for 7 out of the 14 women.

Firstly, the pivotal quantity for 95% confidence interval for the true proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of women who find success with this new treatment = $\frac{7}{14}$ = 0.50

n = sample of women = 14

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the true proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.50-1.96 \times {\sqrt{\frac{0.50(1-0.50)}{14} } }$ , $0.50+1.96 \times {\sqrt{\frac{0.50(1-0.50)}{14} } }$ ]

= [0.238 , 0.762]

Therefore, 95% confidence interval for p, the true proportion of all women who will find success with this new treatment is [0.238 , 0.762].

4 0

3 years ago

Will give brainlst Have a nice day

Zolol [24]

Step-by-step explanation:

9) given

$12x = 4(x + 2) + 20 \\ 12x = 4x + 8 + 20 \\ 8x = 28 \\ x = 28 \div 8 \\ = 3.5$

10)standard form equation: y=mx+c

where m = slope and c = y-intercept

given m = 8, c = 12,

equation of line :

$y = 8x + 12$

4 0

3 years ago

A rectangle is three centimeters.longer than it is wide. if its length were to be decreased by two centimeters, its area would d

Scorpion4ik [409]

Given/equations formed from text:
I: l=w+3
II: A=l*w
III: new area B=(l-2)*w
IV: B=A-30

substitute l in II with I to remove l:
II': A=l*w=
(w+3)*w=
w^2+3w

substitute l in III with I to remove l:
III': B=(l-2)*w=
(w+3-2)*w=
(w+1)*w=
w^2+w

substitute A and B from II' and III' into IV:
B=A-30
w^2+w=w^2+3w-30
30=2w
w=15

insert w=15 into I:
l=15+3=18
->
A) dimensions of full size rectangle are width 15 and length 18
dimensions of reduced size rectangle are width 15 and length 16

B) full size: 15*18=10*18+5*18=180+90=270cm^2
reduced size: 15*16=10*16+5*16=160+80=240cm^2

7 0

4 years ago

What is -3(-6z-5)-9z

andreyandreev [35.5K]

If you factor it then your answer will be -3(-3z-5) if you simplify the answer is 9z+15

7 0

3 years ago

Read 2 more answers