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Shalnov [3]
2 years ago
10

From a point on a cliff 75 feet above water level, an observer can see a shipThe angle of depression to the ship is d^ How far i

s the ship from the base of the to the nearest foot?
Mathematics
1 answer:
Alexandra [31]2 years ago
8 0

Answer:

52feet

Step-by-step explanation:

The set up will be a right angle

Let the angle of depression be 30°

The height above the sea level will be the opposite

The distance of the ship from the base is x (adjacent)

Using TOA

Tan theta = opposite/adjacent

Tan 30 = 30/x

x = 30/tan 30

x = 30/0.5774

x = 51.96

x ≈ 52 feet to the nearest foot

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It cost $8.31 to power one laptop computer for one year. How much does it cost to power 10 for one week.
svp [43]

Answer:

$1.60

Step-by-step explanation:

1 year have 52 weeks.

8.31/52=0.16

0.16*10= 1.60

5 0
3 years ago
Which is the approximate solution to the system y = 0.5x + 3.5 and y = − 2/3 x + 1/3 shown on the graph? (–2.7, 2.1) (–2.1, 2.7)
AlekseyPX

Answer:

The approximate solution to the system is (-2.7, 2.1).

Step-by-step explanation:

To solve the system of equations \begin{bmatrix}y=0.5x+3.5\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix} you must:

\mathrm{Rationalize\:equations}\\\\\begin{bmatrix}y=\left(\frac{1}{2}\right)x+\left(\frac{7}{2}\right)\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix}

\mathrm{Subsititute\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\begin{bmatrix}-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\end{bmatrix}

\mathrm{Isolate}\:x\:\mathrm{for}\:-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\\\\-\frac{2}{3}x=\frac{19}{6}+\frac{1}{2}x\\\\-\frac{7}{6}x=\frac{19}{6}\\\\6\left(-\frac{7}{6}x\right)=\frac{19\cdot \:6}{6}\\\\-7x=19\\\\x=-\frac{19}{7}\approx-2.7

\mathrm{For\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\mathrm{Subsititute\:}x=-\frac{19}{7}\\\\y=-\frac{2}{3}\left(-\frac{19}{7}\right)+\frac{1}{3}\\\\y=\frac{15}{7}\approx 2.1

The approximate solutions to the system of equations are:

x=-2.7 ,\:y=2.1

5 0
3 years ago
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DochEvi [55]

Answer:

28 and 30

Step-by-step explanation:

'x' = 1st consecutive #

'x+2' = 2nd consecutive #

x + x+2 = 58

2x + 2 = 58

2x = 56

x = 28

x+2 = 30

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