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2 years ago

What interger is equivalent to -(-7)?

Mathematics

1 answer:

Lelechka [254]2 years ago

6 0

Positive 7 (two negitives make a positive)

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Write the equation of the circle centered at ( 7 , − 5 ) (7,-5) with diameter 16

galina1969 [7]

The equation of a circle is (x - h)² + (y - k)² = radius² where (h, k) is the center.

If the diameter is 16, then the radius is 8.

Your equation is:
(x - 7)² + (y + 5)² = 64

3 0

3 years ago

Tickets for a concert were \$5$5dollar sign, 5 for each child and \$8$8dollar sign, 8 for each adult. At one of the concerts, ea

OlgaM077 [116]

Answer:

Step-by-step explanation:

Let c represent the number of children that attended the concert.

Let a represent the number of adults that attended the concert.

At one of the concerts, each adult brought 4 children with them, and 10 children attended without an adult. This means that the number of children that attended is

c = 4a + 10

Tickets for a concert were $5 for each child and $8 for each adult. The total ticket sales were $1730. It means that

5c + 8a = 1730

Therefore, the systems of equations that can be solved to determine the number of children, c, and adults that attended the concert is

c = 4a + 10

5c + 8a = 1730

4 0

3 years ago

R= m/2 (c + K) for k

Wewaii [24]

Answer:

$\bold{K=\frac{2r}m-c=\frac{2r-cm}m}$

Step-by-step explanation:

$\bold{r= \frac m2 (c + K)}\\^{\div\frac m2}\qquad^{\div\frac m2}\\ \bold{r\cdot\frac2m=c+K}\\{}\ ^{-c}\qquad^{-c}\\\bold{\frac{2r}m-c=K}$

Or if you mean r= m/[2(c + K)]

$\bold{\quad r\ =\ \frac m{ 2(c + K)}}\\^{\cdot(c+K)}\quad^{\cdot(c+K)}\\ \bold{r(c+K)=\frac m2}\\{}\qquad ^{\div r}\qquad^{\div r}\\\bold{c+K=\frac m2\cdot\frac1r}\\{}\quad^{-c}\qquad^{-c}\\\bold{K=\frac m{2r}-c}$

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2 years ago

HELP PLS! A kiddie pool is 9 feet long and 6 feet wide. Surrounding wach side of the kiddie pool is a cement walkway of uniform

Olenka [21]

Answer:

wait I will edit and answer it in a few minutes

8 0

1 year ago

suppose that a computer chip company has just shipped 10,000 computer chips to another computer company. Unfortunately, 20 of th

Sedaia [141]

Answer:

20÷10=2. 10,000÷10=1,000

Therefore, the probability of two randomly selected chips being defective is 2 in 1,000 or 2/1,000

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3 years ago