Since you are in middle school, I will assume simple shapes such as rectangles and squares
area=legnth times width
therefor
width=area/legnth and
legnth=area/width
Given:
The figure of a right angle triangle.

Hypotenuse =
in.
To find:
The missing lengths of the sides.
Solution:
In the given right angle triangle both legs a and b are equal, and hypotenuse is
in.
Using Pythagoras theorem, we get


![[\because a=b]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%3Db%5D)

Divide both sides by 2.

Taking square root on both sides.


Side cannot be negative. So,

Thus, the missing side lengths are a=9 in and b=9 in.
Therefore, the correct option is C.
180 seconds hope this helps
ABC = 408
C + 7 = B
A + 5 = B
B - 7 + B - 5 + B = 408
3B - 12 = 408
+ 12 = +12
3B = 420
/3 = /3
B = 120
A = 115
C = 113
The answer is A = 115, Abel has $ 115
Answer:
8 and 8√3
Step-by-step explanation:
Sin90 = b/8
1 x 8 =b
b=8
Tan 30 = 8/a
1/√3 = 8/a
a=8√3