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Doss [256]
3 years ago
7

P(x) = 3x2 - 7x + 11, find P(9).

Mathematics
2 answers:
nadya68 [22]3 years ago
6 0
You need to substitute 9 with every x value in the equation. 
So, 3(9)^2-7(9)+11
p(x)= 191
const2013 [10]3 years ago
5 0
P(9) = 3\cdot9^2-7\cdot 9 +11 = 3\cdot 81 - 63 +11  = 243-63 + 11 =\\=180+11=191
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Can someone please help me with all of these problems. They are a ton of them and they are due tomorrow. PLEASE AND THANK YOU
Masteriza [31]

15. \frac{x}{5} - g = a

Add "g" on both sides

\frac{x}{5}  = a +g

Multiply 5 on both sides to get x by itself

x = 5(a + g)

x = 5a + 5g


18. a = 3n + 1

Subtract 1 on both sides

a - 1 = 3n

Divide 3 on both sides to get n by itself

\frac{a - 1}{3}  = \frac{a}{3} -\frac{1}{3} = n


21. M = T - R

Add "R" on both sides to get "T" by itself

M + R = T


24. 5p + 9c = p

Subtract "5p" on both sides

9c = p - 5p

9c = -4p

Divide 9 on both sides to get "c" by itself

c = \frac{-4p}{9} or c = \frac{-4}{9} p


27. 4y + 3x = 5

Subtract "4y" on both sides

3x = 5 - 4y

Divide 3 on both sides to get "x" by itself

x = \frac{5-4y}{3}

x = \frac{5}{3} -\frac{4y}{3}

7 0
3 years ago
How do you figure out #9 and #10
Ann [662]
#9 the sum of two angles is 90 degrees, creating a right angle.

#10 the sum of the two angles is 180 because the form a supplementary angle
4 0
3 years ago
Factorise 2p^2 - p - 10<br> (2p squared)
velikii [3]

2p² - p - 10 = 0

2 = a

- 1 = b

- 10 = c

To factor, find two numbers that multiply to equal a·c and also that have a sum of b

2p² + 4p - 5p - 10 = 0

2p (p + 2) - 5 (p + 2) = 0

<h3>Answer: ( 2p - 5 ) ( p + 2 ) = 0</h3>
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3 years ago
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Gekata [30.6K]

Answer:

C

Step-by-step explanation:

3 0
3 years ago
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Two students, Ann and Max, factored the trinomial 4x2-6x -4. Ann factored it as 2(k 2xx+ 1) and Max factored it as (-2)4x+2), In
marishachu [46]

Given trinomial 4x^2-6x-4.

In order to factor a trinomial, we need to factor out greatest common factor (GCF).

In the given trinomial, we have terms 4x^2, -6x, -4.

We can see that all terms can be divided by a greatest number 2.

Therefore, greatest common factor would be 2 there.

We need to factor out 2 first.

On factoring out 2, we get

2(2x^2 -3x -2).

Now, we need to factor out trinomial 2x^2 -3x -2 now.

We can factor a trinomial by applying product sum rule.

We have a=2,b=-3,c=-2.

ac= 2*-2 = -4 and b=-3.

So, we need to find the factors of -4 that add upto -3.

Factors of -4 would be -4 and 1.

Let us replace -3x by -4x +1x in 2x^2 -3x -2 trinomial

2x^2 -3x -2 could be rewrite as 2x^2 -4x +1x -2.

Making it into two groups and factoring out GCF of each group.

We get

(2x^2 -4x) +(1x - 2)

2x(x-2) +1(x-2)

=(x-2)(2x+1)

Therefore, final factors of the trinomial is 2(x-2)(2x+1).

So, Ann factored form 2(x-2)(2x+1) is correct.

8 0
3 years ago
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