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taurus [48]
3 years ago
8

Doris put $4000 in a 2-year CD paying 6% interest, compounded monthly. After 2 years,she withdrew all her money. What was the am

ount of the withdrawl?
Mathematics
2 answers:
erastova [34]3 years ago
8 0
A=4,000×(1+0.06÷12)^(12×2)
A=4,508.64
Zanzabum3 years ago
5 0

Answer:

The amount of the withdrawal after 2 years will be $ 4508.64

Step-by-step explanation:

Given : Doris put $ 4000 in a 2-year CD paying 6% interest, compounded monthly.          

We have to find the amount of the withdrawal.

Since given the principal amount is $ 4000 for 2 years  and

Rate is 6% = 0.06  

Since, interest is calculated compounded monthly

so monthly interest rate is \frac{6}{1200}

Using Formula for compound interest

A=P(1+r)^n

Where A is amount

r is interest rate

n is time period

Substitute, we have,

A=4000\left(1+\frac{6}{1200}\right)^{\left(12\cdot2\right)}

Simplify, we have ,

A = 4508.64

Thus, The amount of the withdrawal after 2 years will be $ 4508.64

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A food company sells salmon to various customers. The mean weight of the salmon is 44 lb with a standard deviation of 3 lbs. The
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Correct question:

A food company sells salmon to various customers. The mean weight of the salmon is 44 lb with a standard deviation of 3 lbs. The company ships them to restaurants in boxes of 9 ​salmon, to grocery stores in cartons of 16 ​salmon, and to discount outlet stores in pallets of 64 salmon. To forecast​ costs, the shipping department needs to estimate the standard deviation of the mean weight of the salmon in each type of shipment. Complete parts​ (a) and​ (b) below.

a. Find the standard deviations of the mean weight of the salmon in each type of shipment.

b. The distribution of the salmon weights turns out to be skewed to the high end. Would the distribution of shipping weights be better characterized by a Normal model for the boxes or pallets?

Answer:

Given:

Mean, u = 44

Sd = 3

The company ships in boxes of 9, cartons of 16 and pallets of 64.

a) For the standard deviations of the mean weight of the salmon in each type of shipment, lets use the formula: \frac{s.d}{\sqrt{u}}

i) For the standard deviation of the mean weight of salmon in boxes of 9, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{9}}

= \frac{3}{3} = 1

The standard deviation = 1

ii) For the standard deviation of the mean weight of salmon in cartons of 16, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{16}}

= \frac{3}{4} = 0.75

Standard deviation = 0.75

iii) For the standard deviation of the mean weight of salmon in pellets of 64, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{64}}

= \frac{3}{8} = 0.375

Standard deviation = 0.375

b) The distribution of shipping weights would be better characterized by a Normal model for the pallets, because regardless of the underlying distribution, the sampling distribution of the mean approaches the Normal model as the sample increases.

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