Factor by grouping step by step 7c^4-4c^3+28c^2-16c

Mathematics

1 answer:

matrenka [14]3 years ago

3 0

After factor by grouping $7c^4-4c^3+28c^2-16c$ we get $c(7c-4)(c^2+4)$

Step-by-step explanation:

We need to factor the term:

$7c^4-4c^3+28c^2-16c$

Taking c common:

$7c^4-4c^3+28c^2-16c\\c(7c^3-4c^2+28c-16)$

Now making groups:

$c(7c^3+28c-4c^2-16)$

Now factorizing by groups:

$c(7c^3+28c-4c^2-16)\\=c(7c(c^2+4)-4(c^2+4))\\=c((7c-4)(c^2+4))\\=c(7c-4)(c^2+4)$

So, after factor by grouping $7c^4-4c^3+28c^2-16c$ we get $c(7c-4)(c^2+4)$

Keywords: factor by grouping, factorization

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