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3 years ago

Find the scale factor used to produce the image in each of the following:

Mathematics

1 answer:

kiruha [24]3 years ago

5 0

Answer:

A: 5

B: 3.5

Step-by-step explanation:

In a, measurements of the sides from the left can be divided by the corresponding sides measurements to get five.

ex. 15÷3=5, 20÷4=5, and 25÷5=5

In b, the same can be said but for the scale factor 3.5

ex. 28÷8=3.5, 14÷4=3.5

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Help answer please!!

12345 [234]

Answer:

h = 19.7 ft.

Step-by-step explanation:

Use the Pythagoras Theorem

$(Hypotenuse)^2 = (Base)^2 + (Perpendicular)^2\\\\(20)^2=(3.5)^2+(h)^2\\400=12.25+h^2\\400-12.25=h^2\\387.75=h^2\\$

Now we take square root on both sides,

$\sqrt{387.75} =\sqrt{h^2}\\19.69=h\\h=19.7\ ft\\$

so the value of h equals 19.7 ft.

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2 years ago

PLZZ help me asap!! 70points!!

weqwewe [10]

Answer:

1. Given.

2. Opposite Sides OF A Parallelogram Are Congruent.

3. Corresponding Angles Postulate.

4. Substitution

5. ASA Congruence Postulate

6. Definition Of A Parallelogram.

Step-by-step explanation:

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3 years ago

What are the numbers that are either negative or greater than 5

Reptile [31]

postive or greater6 7 8 9 10

negative or less 4 3 2 1 0

7 0

3 years ago

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$