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alina1380 [7]
3 years ago
14

Can someone answer this question for me?

Mathematics
1 answer:
hjlf3 years ago
6 0

Answer:

That is a right angles triangle which means to get the area: multiply the base(14.1)to be the height (9.8) divided by 2.

Formula : half the base times the height given. Your answer is to be squared and don't forget the correct unit.

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What is the percent equation for 46% of 127?
Brut [27]

Answer:

46% of 127 is 58.42

Step-by-step explanation:

46/100 = x/127

Cross multiply

46 × 127 = 100 × x

5,842 = 100x

Divide both sides by 100

58.42 = x

3 0
3 years ago
An interior designer sketches a design for a rectangular rug. The dimensions of a sketch are 4 inches by 7.5 in. The dimensions
Black_prince [1.1K]

3,000 in.

(4 x 10) + (7.5 x 10) = 3000


The dimensions on the sketch are 10 times less than the actual rug.


40 in., 7.5 in.


The drawing lengths are ten times more, so you just multiply the dimensions by 10, and then multiply the product you find out to find the actual area of the rug.

4 0
4 years ago
3 1/8 rounded to the closest benchmark
Karolina [17]
I have the answer but brainly is not working
3 0
3 years ago
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Which expression is equivalent to Left-bracket log 9 + one-half log x + log (x cubed + 4) Right-bracket minus log 6? log StartFr
dybincka [34]

Answer:

  \log{\dfrac{3\sqrt{x}(x^3+4)}{2}}

Step-by-step explanation:

\log{9}+\dfrac{1}{2}\log{x}+\log{(x^3+4)}-\log{6}=\log{\left(\dfrac{9x^{\frac{1}{2}}(x^3+4)}{6}\right)}\\\\=\boxed{\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}}\qquad\text{matches choice A}

__

The applicable rules of logarithms are ...

  log(ab) = log(a) +log(b)

  log(a/b) = log(a) -log(b)

  log(a^b) = b·log(a)

3 0
3 years ago
These figures are similar. The area of one is given. Find the area of the other. PLZ HELP
stellarik [79]

Answer:

12 in squared

Step-by-step explanation:

Since the side on the bigger figure is 6 and the smaller figure‘s side is 3, that means the smaller figure is half the size of the big figure.

So.. 24 divided by 2 is 12

6 0
3 years ago
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