Answer:
im having the same problem
Step-by-step explanation:
Answer:
The probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3) = 0.00621
Step-by-step explanation:
This is a normal distribution problem
The mean of the sample = The population mean
μₓ = μ = 4 ounces
But the standard deviation of the sample is related to the standard deviation of the population through the relation
σₓ = σ/√n
where n = Sample size = 100
σₓ = 1.2/√100
σₓ = 0.12
The probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3)
To do this, we first normalize/standardize the 4.3 ounces
The standardized score for any value is the value minus the mean then divided by the standard deviation.
z = (x - μ)/σ = (4.3 - 4)/0.12 = 2.5
To determine the probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3) = P(z > 2.5)
We'll use data from the normal probability table for these probabilities
P(x > 4.3) = P(z > 2.5) = 1 - P(z ≤ 2.5) = 1 - 0.99379 = 0.00621
The histogram representing the data is attcwhwd in the picture below.
Answer:
C On exactly 25% of these days, Shane drank 3 to 4 glasses of water.
Step-by-step explanation:
The number of 8 - ounce glasses is represented on the x - axis and the number of days on the y - axis.
From the histogram ;
Shane drank 1 - 2 glasses on exactly 1 day
Shane drank 3 - 4 glasses on exactly 3 days
Shane drank 5 - 6 glasses on exactly 6 day
Total number of days = 12
60% of 12 = 7.2
On exactly 60% of the days, which is 7.2 days, number of glasses drunk isn't covered by the histogram
25% of 12 ; 0.25 * 12 = 3 days
From the histogram, number of glasses consumed is 3 - 4 glasses ; which is the only true statement about the histogram in the options given.
