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Aleksandr [31]
3 years ago
12

Students at Maple school earned $708 selling candles. They want to accumulate $2000 for a club trio. What percent of their goal

has been reached
Mathematics
1 answer:
Sholpan [36]3 years ago
5 0

Answer:

<u>The correct answer is 35.4%</u>

Step-by-step explanation:

Let's check the information provided in the question:

Savings goal = US$ 2,000 for the club trip

Earnings for the candles selling = US$ 708

For calculating the accumulated percentage, we can do it this way:

Accumulated percentage = Earnings / Savings goal

Accumulated percentage = 708 / 2,000 * 100

Accumulated percentage = 0.354 * 100

<u>Accumulated percentage = 35.4%</u>

<u>Students at Maple School has accumulated 35.4% of their savings goal with the candles selling.</u>

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Answer:

32.63

Step-by-step explanation:

since arizbeth is spending $20.08 to put 8 gallons in her car the first step is to divide 20.08 by 8.Then since you have per gallon you have to figure out what 13 gallons is so you multiply per gallon by 13

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3 years ago
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3 years ago
The sum of two numbers is -9. The difference of the two numbers is -41. What are the two numbers?
Nataly [62]

Answer:

the two numbers are 16 and -25

Step-by-step explanation:

Let the two numbers be x and y

x+y=-9

x-y=-41

By substitution

y=-9-x

x-(-9-x)=-41

x+9+x=-41

2x=-41-9

2x=-50

x=-25

y=-9-(-25)

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3 years ago
Fifty people were surveyed about their favorite pizza topping. The results of the survey are displayed in the circle graph. How
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3 years ago
A food company sells salmon to various customers. The mean weight of the salmon is 37 lb with a standard deviation of 2 lbs. The
brilliants [131]

Answer:

The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.

Step-by-step explanation:

The mean sample of the sum of n random variables is

\overline{X} = \frac{X_1+X_2+...+X_n}{n}

If X_1, ..., X_n are indentically distributed and independent, like in the situation of the problem, then the variance of X_1 + .... + X_n will be the sum of the variances, in other words, it will be n times the variance of X_1 .

However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus \overkine{X} = \frac{V(X_1)}{n} and as a result, the standard deviation of \overline{X} is the standard deviation of X_1 divided by \sqrt{n} .

Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:

  • Restaurants: We have boxes with 9 salmon each, so it will be \frac{2}{\sqrt{9}} = \frac{2}{3}
  • Grocery stores: Each carton has 49 salmon, thus the standard deviation is \frac{2}{\sqrt{49}} = \frac{2}{7}
  • Discount outlet stores: Each pallet has 64 salmon, as a result, the standard deviation is \frac{2}{\sqrt{64}} = \frac{1}{4}

We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.

7 0
3 years ago
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