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Vaselesa [24]
3 years ago
14

34 rounded to the nearest 10 with a 69 degree angle

Mathematics
2 answers:
givi [52]3 years ago
3 0

Question 2:

During his workouts last week, Allen jogged the same amount of time each day for 6 days. Use the following information to determine the number of minutes Allen jogged each day:

During each workout, he jogged and he rode his bike.

He rode his bike for 45 minutes each day.

He worked out for a total of 360 minutes last week.

What is the number of minutes that Allen jogged each day last week? Enter your answer in the box below. PLS HELP ME I DONT WANNA GET A F PLSSSSSSSSS

girl in red fan girl
2 years ago
think its 15
Alenkinab [10]3 years ago
3 0

Answer:

seriously....69 degrees?

Step-by-step explanation:

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John, Sally, and Natalie would all like to save some money. John decides that it
brilliants [131]

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2)  y=100x+300

Part 3) \$12,300

Part 4) \$2,700

Part 5) Is a exponential growth function

Part 6) A=6,000(1.07)^{t}

Part 7) \$11,802.91

Part 8)  \$6,869.40

Part 9) Is a exponential growth function

Part 10) A=5,000(e)^{0.10t}    or  A=5,000(1.1052)^{t}

Part 11)  \$13,591.41

Part 12) \$6,107.01

Part 13)  Natalie has the most money after 10 years

Part 14)  Sally has the most money after 2 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

y=mx+b

The slope is equal to

m=\$100\ per\ month

The y-intercept or initial value is

b=\$300

so

y=100x+300

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

see part 1)

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

so

10\ years=10(12)=120 months

For x=120 months

substitute in the linear equation

y=100(120)+300=\$12,300

Part 4) How much money will John have after 2 years?

Remember that

1 year is equal to 12 months

so

2\  years=2(12)=24\ months

For x=24 months

substitute in the linear equation

y=100(24)+300=\$2,700

Part 5) What type of exponential model is Sally’s situation?

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt} 

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

P=\$6,000\\ r=7\%=0.07\\n=1

substitute in the formula above

A=6,000(1+\frac{0.07}{1})^{1*t}\\  A=6,000(1.07)^{t}

therefore

Is a exponential growth function

Part 6) Write the model equation for Sally’s situation

see the Part 5)

Part 7) How much money will Sally have after 10 years?

For t=10 years

substitute  the value of t in the exponential growth function

A=6,000(1.07)^{10}=\$11,802.91 

Part 8) How much money will Sally have after 2 years?

For t=2 years

substitute  the value of t in the exponential growth function

A=6,000(1.07)^{2}=\$6,869.40

Part 9) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt} 

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

P=\$5,000\\r=10\%=0.10

substitute in the formula above

A=5,000(e)^{0.10t}

Applying property of exponents

A=5,000(1.1052)^{t}

 therefore

Is a exponential growth function

Part 10) Write the model equation for Natalie’s situation

A=5,000(e)^{0.10t}    or  A=5,000(1.1052)^{t}

see Part 9)

Part 11) How much money will Natalie have after 10 years?

For t=10 years

substitute

A=5,000(e)^{0.10*10}=\$13,591.41

Part 12) How much money will Natalie have after 2 years?

For t=2 years

substitute

A=5,000(e)^{0.10*2}=\$6,107.01

Part 13) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

Part 14) Who will have the most money after 2 years?

Compare the final investment after 2 years of John, Sally, and Natalie

Sally has the most money after 2 years

3 0
3 years ago
How do i do this? geometry
iren [92.7K]

Answer:

80?

Step-by-step explanation:

the total amount of degrees  in a hexagon is 720. Divide that by 6 and you get 120. Each corner is 120. It doesnt have a right angle measure on it so it has to be lowerer then 90.

3 0
2 years ago
Solve for x.<br> 9/x = -6
yan [13]

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>

5 0
3 years ago
Read 2 more answers
A group of 120 people touring Europe includes 45 people who speak French, 42 who speak Spanish, and 50 who speak neither languag
lianna [129]

Answer : P(\text{this group will speak both French and Spanish})=0.141666666

Explanation:

Since we have given that

n(U) = 120, where U denotes universal set ,

n(F) = 45, where F denotes who speak French,

n(S) = 42 , where S denotes who speak Spanish,

n(F∪S)' = 50

n(F∪S) = n(U)-n(F∪S) = 120-50 = 70

Now, we know the formula, i.e.

n(F∪s) = n(F)+n(S)-n(F∩S)

⇒  70    = 45+42-n(F∩S)

⇒ 70  =  87- n(F∩S)

⇒ 70-87 = -n(F∩S)

⇒ -17 = -n( F∩S)

⇒  17 = n(F∩S)

P(\text{this group will speak both French and Spanish})= \frac{17}{120}\\P(\text{this group will speak both French and Spanish})=0.141666666

3 0
2 years ago
Find f(-5) of f (x) = x + 1<br> 1) 4<br> 2) 5<br> 6) 6
Alex
F(-5) just means that your substituting the number -5 for every x value. So if you have x+1 this would be -5+1 which is -4
7 0
3 years ago
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