The given polynomials can be rewritten in simplified form by dividing by
a power of the variable of the polynomial.
Responses:
<h3>Which method are used to approximate fractional polynomials?</h3>
The possible functions based on a similar question posted online are;




The options are;
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d. 1

Therefore;




Therefore;



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The hypothetical lab graph might miss 0 k, because the gas might liquefy before the 0 K.
<h3>Volume of ideal gas at zero kelvin temperature</h3>
The volume of an ideal gas is directly proportional to the absolute temperature or Kelvin temperature of the gas. The volume of ideal gas will be zero at zero Kelvin or -273 degrees Celsius.
<h3>Volume of real gas at zero kelvin temperature</h3>
Real gases or vapors liquefies or turns to liquid before reaching zero Kelvin. This causes the volume of the gas to be greater than zero at zero Kelvin temperature.
Thus, the hypothetical lab graph might miss 0 k, because the gas might liquefy before the 0 K.
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The repetition of the phrase "do i dare?" three times indicates that: he is indecisive.
One of the central themes that were explored in "The Love Song of J. Alfred Prufrock" is the social anxiety that he experiences.
He is worried about people's conception of him and that is why before he descends the stairs, he wonders if he can dare face the people because of the bald spot in the middle of his head and several other insecurities.
So, option A is correct.
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Answer:
Can't see the question properly
Explanation:
Based on the graph given, it can be deduced from the computation that the value of y will be -8.
Point C is given as (-10 , -2) and D = (10 , 6)
The Slope of line CD = ( 6 - (-2) /( 10 - (-10) = 8/20 = 2/5
Since EF is parallel to line CD
, the slope of EF = 2/5
Equation y = (2/5)x + c
5y = 2x + 5c
It passes through F ( 6 , -4)
= 5(-4) = 2*6 + 5c
= -20 = 12 + 5c
5c = -32
5y = 2x - 32
Point E ( - 4 , y)
5y = 2(-4) - 32
5y = -8 - 32
5y = -40
y = -8
Therefore, the value of y is -8.
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