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adoni [48]
3 years ago
14

According to a magazine, a cleaning solution of 5% bleach will remove mildew from a shower or tub.

SAT
1 answer:
zzz [600]3 years ago
3 0
A quart has 32oz in it. If the solution needs 5% bleach then all you do is multiply 32*(5/100) or 32*.05. Either way, the answer is 1.6. So you need 1.6 oz to make a quart 5% bleach solution.
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Match the following functions with functions that exhibit a similar behavior for large values of $x. $.
Delvig [45]

The given polynomials can be rewritten in simplified form by dividing by

a power of the variable of the polynomial.

Responses:

  • \dfrac{2 + 3 \cdot x^2 + x^4}{x + 3 \cdot x^3  + x^4}\ \Rightarrow  \ \underline{ d. \ 1}
  • \dfrac{5 \cdot x + 2 \cdot x^2 + x^5}{5 \cdot x + 4 \cdot x^2  + x^9}  \Rightarrow \underline{a. \ \dfrac{1}{x^4}}
  • \dfrac{7 \cdot x +2}{4 \cdot x  + x^3}  \Rightarrow \underline{ \ b. \  \dfrac{7}{x^2}}
  • \dfrac{4 + 2 \cdot x^2 }{5 \cdot x + 4 \cdot x^3  + x^5} \Rightarrow \underline{  \ c. \  \dfrac{2}{x^3}}

<h3>Which method are used to approximate fractional polynomials?</h3>

The possible functions based on a similar question posted online are;

\dfrac{2 + 3 \cdot x^2 + x^4}{x + 3 \cdot x^3  + x^4}

\dfrac{5 \cdot x + 2 \cdot x^2 + x^5}{5 \cdot x + 4 \cdot x^2  + x^9}

\dfrac{7 \cdot x +2}{4 \cdot x  + x^3}

\dfrac{4 + 2 \cdot x^2 }{5 \cdot x + 4 \cdot x^3  + x^5}

The options are;

a. \hspace{0.15 cm}\dfrac{1}{x^4}<em />

b. \hspace{0.15 cm}\dfrac{7}{x^2}

c. \hspace{0.15 cm}\dfrac{2}{x^3}

d. 1

  • \mathbf{\dfrac{2 + 3 \cdot x^2 + x^4}{x + 3 \cdot x^3  + x^4}}

\mathbf{\dfrac{\frac{2}{ x^4}+\frac{x 3 \cdot x^2}{ x^4} + \frac{ x^4}{ x^4} }{\frac{x}{ x^4}  + \frac{3 \cdot x^3 }{x^4}  +\frac{x^4}{x^4} } }\approx \dfrac{0 + 0 + 1}{0 + 0 + 1} \approx 1

Therefore;

The \ match \ for \ \dfrac{2 + 3 \cdot x^2 + x^4}{x + 3 \cdot x^3  + x^4}\ is \ d. \ 1

  • \mathbf{\dfrac{5 \cdot x + 2 \cdot x^2 + x^5}{5 \cdot x + 4 \cdot x^2  + x^9}}

\dfrac{5 \cdot x + 2 \cdot x^2 + x^5}{5 \cdot x + 4 \cdot x^2  + x^9} = \mathbf{ \dfrac{\frac{5 \cdot x}{x^5}  + \frac{2 \cdot x^2}{x^5}  +\frac{x^5}{x^5} }{\frac{5 \cdot x}{x^5} + \frac{4 \cdot x^2}{x^5}   + \frac{x^9}{x^5} }} \approx \dfrac{0 + 0 + 1}{0 + 0 + x^4} \approx \dfrac{1}{x^4}

The \ match \ for \ \dfrac{5 \cdot x + 2 \cdot x^2 + x^5}{5 \cdot x + 4 \cdot x^2  + x^9} \ is \ a. \ \dfrac{1}{x^4}

  • \mathbf{\dfrac{7 \cdot x +2}{4 \cdot x  + x^3}}

\dfrac{7 \cdot x +2}{4 \cdot x  + x^3} = \dfrac{7 \cdot x }{4 \cdot x  + x^3}+ \dfrac{ 2}{4 \cdot x  + x^3} = \mathbf{ \dfrac{7 }{4   + x^2}+ \dfrac{ 2}{4 \cdot x  + x^3}}  \approx \dfrac{7}{x^2}

Therefore;

The \ match \ for \ \dfrac{7 \cdot x +2}{4 \cdot x  + x^3} \ is \ b. \  \dfrac{7}{x^2}

  • \mathbf{\dfrac{4 + 2 \cdot x^2 }{5 \cdot x + 4 \cdot x^3  + x^5}}

\dfrac{4 + 2 \cdot x^2 }{5 \cdot x + 4 \cdot x^3  + x^5} =\mathbf{ \dfrac{\frac{4}{x^2}  + \frac{2 \cdot x^2 }{x^2} }{\frac{5 \cdot x}{x^2}  + \frac{4 \cdot x^3}{x^2}   +\frac{x^5}{x^2}}} \approx \dfrac{0  +2}{0 +4 \cdot x  +x^3}  \approx \dfrac{2}{x^3}

The \ match \ for \ \dfrac{4 + 2 \cdot x^2 }{5 \cdot x + 4 \cdot x^3  + x^5} \ is \ c. \  \dfrac{2}{x^3}

Learn more about polynomials here:

brainly.com/question/1528517

brainly.com/question/12006853

6 0
3 years ago
Absolute zero is measured as 0 k, and is defined as the lowest possible temperature, at which the volume of a gas would be zero.
jasenka [17]

The hypothetical lab graph might miss 0 k, because the gas might liquefy before the 0 K.

<h3>Volume of ideal gas at zero kelvin temperature</h3>

The volume of an ideal gas is directly proportional to the absolute temperature or Kelvin temperature of the gas. The volume of ideal gas will be zero at zero Kelvin or -273 degrees Celsius.

<h3>Volume of real gas at zero kelvin temperature</h3>

Real gases or vapors liquefies or turns to liquid before reaching zero Kelvin. This causes the volume of the gas to be greater than zero at zero Kelvin temperature.

Thus, the hypothetical lab graph might miss 0 k, because the gas might liquefy before the 0 K.

Learn more about volume of ideal gases here: brainly.com/question/22688430

8 0
2 years ago
In this stanza, prufrock repeats "do i dare?" three times. What does the repetition indicate about his state of mind? he is inde
ASHA 777 [7]

The repetition of the phrase "do i dare?" three times indicates that: he is indecisive.

One of the central themes that were explored in "The Love Song of J. Alfred Prufrock" is the social anxiety that he experiences.

He is worried about people's conception of him and that is why before he descends the stairs, he wonders if he can dare face the people because of the bald spot in the middle of his head and several other insecurities.

So, option A is correct.

Learn more about The Love Song of J. Alfred Prufrock here:

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8 0
3 years ago
Can someone help me pls I’ll give you Brainly
icang [17]

Answer:

Can't see the question properly

Explanation:

3 0
3 years ago
Read 2 more answers
Point e is drawn on the graph so that line ef is parallel to line cd. If the coordinates of point e are (, y), what is the value
netineya [11]

Based on the graph given, it can be deduced from the computation that the value of y will be -8.

Point C is given as (-10 , -2)  and D = (10 , 6)

The Slope of line CD = ( 6 - (-2) /( 10 - (-10) =  8/20  = 2/5

Since EF is parallel to line CD , the slope of EF = 2/5

Equation  y  = (2/5)x  + c

5y = 2x + 5c

It passes through F ( 6 , -4)

= 5(-4) = 2*6  + 5c

= -20 = 12 + 5c

5c = -32

5y = 2x - 32

Point E ( - 4 , y)

5y = 2(-4) - 32

5y = -8 - 32

5y = -40

y = -8

Therefore, the value of y is -8.

Learn more about graphs on:

brainly.com/question/19040584

8 0
2 years ago
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