Mechanical problems since they can be solved and have the second most deaths. I would have the plane go through at least 3 examinations before boarding then one passenger exam before takeoff.
Answer:
businesses could provide internships for them or prep them for getting a job in the real world.
Explanation:
mr clean
The given option that has molecules that are solid at room temperature is; D: Saturated Fats
<h3>Molecules at room temperature </h3>
Fatty acids are organic compounds that are poorly soluble in water but soluble in organic solvents.
The two main types of fatty acids are Saturated fatty acids and Unsaturated fatty acid.
Saturated fatty acids contains no double bond in their carbon chains and as such they are solids at room temperature.
Meanwhile, Unsaturated fatty acids contains double bonds in their carbon chains and are thus liquids at room temperature.
The missing options are;
A) Both saturated and unsaturated fats
B) Cholesterol
C) Saturated fats
D) Unsaturated fats
Read more about molecules at room temperature at; brainly.com/question/17481964
Answer:
ANSWER: No; the angles are not the same, so the polygons do not have the same shape, so there are no similarity transformations between the figures. List all pairs of congruent angles, and write a proportion that relates the corresponding sides for each pair of similar polygons.
From the options given, the only option which would result on having a reduced error margin, is to increase the sample size.
<u>Recall</u><u> </u><u>:</u><u> </u>
<em>Margin of Error</em> = Zcritical × σ/√n
- Increasing the mean would have no impact on the margin of error as it is not a part of the factors which affects the margin of error value.
- Increasing the standard deviation, which is the Numerator will result in an increased margin of error value.
- By raising the confidence level, the critical value of Z will increase, hence widening the margin of error.
- The sample size, n being the denominator, would reduce the value of error margin.
Hence, only the sample size will cause a decrease in the margin of error of the interval.
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