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3 years ago

Identify the type of transformation given the rule M(x, y) = (x, –y).

Mathematics

2 answers:

snow_lady [41]3 years ago

8 0

Reflection across the x-axis

hope it helps

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Gnoma [55]3 years ago

3 0

Reflection about x axis

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(-4,-6) and (3,-7) find the distance between each pair of points

Vlad [161]

Answer:

$5\sqrt{2}$

Step-by-step explanation:

distance between two points:

$d = \sqrt{(x_{2}-x_{1})^{2}+ (y_{2}-y_{1})^{2}}$

we have:

(-4, -6), (3, -7)

$x_{1} = -4$

$y_{1} =-6$

$x_{2} = 3$

$y_{2} =-7$

so we have:

$d =\sqrt{(3-(-4))^{2}+ (-7-(-6))^{2}}\\\\d =\sqrt{(7)^{2}+ (-1)^{2}}\\\\d = \sqrt{49+ 1}\\\\d=\sqrt{50}\\\\d=5\sqrt{2}$

4 0

3 years ago

Read 2 more answers

Compare the functions. f(x)=10x g(x)=5^x h(x)=4x^2+5x select the true statement

antiseptic1488 [7]

Answer:

equals 56

Step-by-step explanation:

7 0

3 years ago

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Angelo's pet rabbit weighs 1 pound less than twice the weight of Carmen's pet rabbit.Angelo's pet rabbit weighs 9 pounds. Write

attashe74 [19]

W=(9+1)/2 i think? its worded strangely

4 0

3 years ago

Help !! Multiply: 2w(w+17)

kotykmax [81]

Answer:

2w^2 + 34w

Step-by-step explanation:

2w(w+17)

Multiply the 2w by each term in the parentheses

2w*w + 2w*17

2w^2 + 34w

6 0

3 years ago

A bee flies 20 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for fifteen minutes. Then i

Ksenya-84 [330]

A. The equation to find the distance of the flowerbed from the hive is: $\frac{x}{20}+\frac{x}{12}+900= 1200$ , where x is the distance.

B. The flowerbed is 2250 feet far from the hive.

<u><em>Explanation</em></u>

Suppose, the distance of the flowerbed from the hive is $x$ feet.

The bee flies 20 feet per second directly to a flowerbed from its hive and flies directly back to the hive at 12 feet per second.

As, $Time=\frac{Distance}{Speed}$

So, the time taken by the bee to reach the flowerbed $= \frac{x}{20}$ seconds and the time taken to fly back to the hive $=\frac{x}{12}$ seconds.

The bee stays at the flowerbed for 15 minutes or (15×60)seconds or 900 seconds and it is away from the hive for a total of 20 minutes or (20×60)seconds or 1200 seconds.

So, the equation will be.......

$\frac{x}{20}+\frac{x}{12}+900= 1200\\ \\ \frac{3x+5x}{60}= 300\\ \\ 8x= 60*300\\ \\ 8x=18000\\ \\ x=\frac{18000}{8}=2250$

Thus, the distance of the flowerbed from the hive is 2250 feet.

5 0

4 years ago