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riadik2000 [5.3K]
3 years ago
14

I have a test please someone help me I need this asp

Mathematics
1 answer:
Paraphin [41]3 years ago
5 0

Answer:

Step-by-step explanation:

the tilt has no impact...

if not tilted then h=14 r=3 vol = pi 3^3 h = 14*9 π

=126π

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What is 68 x 15 - 8 + 22<br><br><br> Anyone wanna talk i'm bored
baherus [9]

Answer:

sorry but i'm in class right now

5 0
2 years ago
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Triangles MNQ and MOP are similar. What is the slope of segment MO?
asambeis [7]

Answer:

D. 3/2

Step-by-step explanation:

The scale factor is 1/2 from OP / NQ = 1/2. Because of that, MQ is equal to half of MP and QP is equal to half of MP. Therefore, QP = MQ = 2. The slope of MO is rise over run which is 6 / 4 or 3 / 2.

5 0
3 years ago
Consider the graph of the sixth-degree polynomial function f.
vekshin1

Answer:

b = 1, c = -1 and d = 4

Step-by-step explanation:

To solve this question the rule of multiplicity of a polynomial is to be followed.

If the multiplicity of a polynomial is even at a point, graph of the polynomial will touch the x-axis.

If the multiplicity of the polynomial is odd, graph will cross the x-axis at that point.

From the graph of function 'f',

f(x) = (x - b)(x - c)²(x - d)³

Since, graph of the function 'f' crosses x-axis at x = 1 and x = 4, multiplicity will be odd and touches the x-axis at x = -1 multiplicity will be even.

So the function will be,

f(x) = (x - 1)[x - (-1)]²(x - 4)³

Therefore, b = 1, c = -1 and d = 4 will be the answer.

7 0
3 years ago
Read 2 more answers
Sandra knows the Pythagorean identity sin 2 ⁡ θ + cos 2 ⁡ θ = 1 . If she is told that 0 ≤ θ ≤ π 2 and cos ⁡ θ = 5 12, what will
slavikrds [6]

Answer:

\text{tan}(\theta)=\frac{\sqrt{119}}{5}

Step-by-step explanation:

We have been given that Sandra knows the Pythagorean identity \text{sin}^2(\theta)+\text{cos}^2(\theta)=1. She is told that 0\leq \theta\leq \frac{\pi}{2} and \text{cos}(\theta)=\frac{5}{12}.

First of all, we will find value of sine theta using the given identity.

\text{sin}^2(\theta)+\text{cos}^2(\theta)=1

\text{sin}^2(\theta)+(\frac{5}{12})^2=1

\text{sin}^2(\theta)+\frac{25}{144}=1

\text{sin}^2(\theta)+\frac{25}{144}-\frac{25}{144}=1-\frac{25}{144}

\text{sin}^2(\theta)=\frac{144-25}{144}

\text{sin}^2(\theta)=\frac{119}{144}

\text{sin}(\theta)=\sqrt{\frac{119}{144}}

\text{sin}(\theta)=\frac{\sqrt{119}}{12}  

\text{tan}(\theta)=\frac{\text{sin}(\theta)}{\text{cos}(\theta)}

\text{tan}(\theta)=\frac{\frac{\sqrt{119}}{12}}{\frac{5}{12}}

\text{tan}(\theta)=\frac{\sqrt{119}*12}{5*12}=\frac{\sqrt{119}}{5}

Therefore, \text{tan}(\theta)=\frac{\sqrt{119}}{5}.

5 0
3 years ago
To
choli [55]

Answer:   B.x^3+4x^2-19x+14 is correct

Step-by-step explanation:

(x + 7)(x2 – 3x + 2)

Multiplying both

x^3-3x^2+2x+7x^2-21x+14

x^3+4x^2-19x+14

7 0
3 years ago
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